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For a four pole, 200 V dc shunt generator having armature resistance of 1 ohms. The current flowing in the armature is 10 A. What is the back emf generated if the terminal voltage of 220 V supply is fed?
- a)230 Volts
- b)210 Volts
- c)190 Volts
- d)200 Volts
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
For a four pole, 200 V dc shunt generator having armature resistance o...
E=V+I*ra
= 220+10*1
=230 Volts.
= 220+10*1
=230 Volts.
Most Upvoted Answer
For a four pole, 200 V dc shunt generator having armature resistance o...
Given data:
- A four pole, 200 V dc shunt generator
- Armature resistance of 1 ohm
- Armature current of 10 A
- Terminal voltage of 220 V supply
To find: The back emf generated by the generator
Solution:
1. Formula: The back emf generated by a dc generator is given by the formula,
Eb = Vt - IaRa
where,
Eb = Back emf generated
Vt = Terminal voltage
Ia = Armature current
Ra = Armature resistance
2. Substituting the given values in the formula,
Eb = 220 - (10 x 1)
Eb = 210 V
3. But the given generator is a four pole generator, which means there are four poles in the field winding.
4. Formula: The back emf generated by a generator is also given by the formula,
Eb = PΦZN / 60A
where,
P = Number of poles
Φ = Flux per pole
Z = Total number of armature conductors
N = Rotational speed in rpm
A = Number of parallel paths in the armature winding
5. Assuming that the generator is operating at a constant speed of 1500 rpm,
6. Formula: The flux per pole can be calculated using the formula,
Φ = Eb / Pω
where,
ω = 2πN / 60
7. Substituting the values in the formula,
ω = 2π x 1500 / 60
ω = 314.16 rad/s
Φ = 210 / (4 x 314.16)
Φ = 0.167 Wb
8. Substituting the values in the second formula,
Eb = 4 x 0.167 x 120 x 1500 / (60 x 2)
Eb = 230 V
Therefore, the back emf generated by the generator is 230 V.
Final Answer: a) 230 Volts
- A four pole, 200 V dc shunt generator
- Armature resistance of 1 ohm
- Armature current of 10 A
- Terminal voltage of 220 V supply
To find: The back emf generated by the generator
Solution:
1. Formula: The back emf generated by a dc generator is given by the formula,
Eb = Vt - IaRa
where,
Eb = Back emf generated
Vt = Terminal voltage
Ia = Armature current
Ra = Armature resistance
2. Substituting the given values in the formula,
Eb = 220 - (10 x 1)
Eb = 210 V
3. But the given generator is a four pole generator, which means there are four poles in the field winding.
4. Formula: The back emf generated by a generator is also given by the formula,
Eb = PΦZN / 60A
where,
P = Number of poles
Φ = Flux per pole
Z = Total number of armature conductors
N = Rotational speed in rpm
A = Number of parallel paths in the armature winding
5. Assuming that the generator is operating at a constant speed of 1500 rpm,
6. Formula: The flux per pole can be calculated using the formula,
Φ = Eb / Pω
where,
ω = 2πN / 60
7. Substituting the values in the formula,
ω = 2π x 1500 / 60
ω = 314.16 rad/s
Φ = 210 / (4 x 314.16)
Φ = 0.167 Wb
8. Substituting the values in the second formula,
Eb = 4 x 0.167 x 120 x 1500 / (60 x 2)
Eb = 230 V
Therefore, the back emf generated by the generator is 230 V.
Final Answer: a) 230 Volts
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For a four pole, 200 V dc shunt generator having armature resistance of 1 ohms. The current flowing in the armature is 10 A. What is the back emf generated if the terminal voltage of 220 V supply is fed?a)230 Voltsb)210 Voltsc)190 Voltsd)200 VoltsCorrect answer is option 'A'. Can you explain this answer?
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For a four pole, 200 V dc shunt generator having armature resistance of 1 ohms. The current flowing in the armature is 10 A. What is the back emf generated if the terminal voltage of 220 V supply is fed?a)230 Voltsb)210 Voltsc)190 Voltsd)200 VoltsCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For a four pole, 200 V dc shunt generator having armature resistance of 1 ohms. The current flowing in the armature is 10 A. What is the back emf generated if the terminal voltage of 220 V supply is fed?a)230 Voltsb)210 Voltsc)190 Voltsd)200 VoltsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a four pole, 200 V dc shunt generator having armature resistance of 1 ohms. The current flowing in the armature is 10 A. What is the back emf generated if the terminal voltage of 220 V supply is fed?a)230 Voltsb)210 Voltsc)190 Voltsd)200 VoltsCorrect answer is option 'A'. Can you explain this answer?.
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