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A sold his bike to B at a loss of 20%. B spent rupees 1500 on its repair and sold the bike to C for 42000, thereby making a profit of 5%. Find the cost of bike for A?
  • a)
    44125
  • b)
    46125
  • c)
    48125
  • d)
    49715
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A sold his bike to B at a loss of 20%. B spent rupees 1500 on its repa...
Cost of A is CP,
cost for B = (80/100)*cp + 1500
selling price of B = 42000 = (105/100)*[(80/100)*cp + 1500] cp = 48125
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Most Upvoted Answer
A sold his bike to B at a loss of 20%. B spent rupees 1500 on its repa...
Let's assume the cost of the bike for A is x rupees.

Loss incurred by A while selling the bike to B is 20% of x, which is (20/100)*x = 0.2x.

The selling price of the bike to B is x - 0.2x = 0.8x.

B spent 1500 rupees on repairing the bike. So the total cost for B is 0.8x + 1500 rupees.

Profit made by B while selling the bike to C is 5% of the total cost for B, which is (5/100)*(0.8x + 1500) = 0.05*(0.8x + 1500).

The selling price of the bike to C is the total cost for B + profit made by B, which is (0.8x + 1500) + 0.05*(0.8x + 1500) = 42000.

Simplifying the equation:
0.8x + 1500 + 0.04x + 75 = 42000
0.84x + 1575 = 42000
0.84x = 40425
x = 40425/0.84
x ≈ 48125

Therefore, the cost of the bike for A is approximately 48125 rupees.

Hence, option C (48125) is the correct answer.
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Community Answer
A sold his bike to B at a loss of 20%. B spent rupees 1500 on its repa...
Cost of A is CP,
cost for B = (80/100)*cp + 1500
selling price of B = 42000 = (105/100)*[(80/100)*cp + 1500] cp = 48125
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