A vendor sold two magazines namely A and B. He sold magazine ‘A&...
20% of x = 25% of y ; x + y = 450
x/y = 5/4
Difference = Rs.50
View all questions of this test
A vendor sold two magazines namely A and B. He sold magazine ‘A&...
A for $5 and magazine B for $8. He sold a total of 10 magazines and made a total of $70. Let's solve this problem using algebra.
Let's assume the vendor sold x copies of magazine A and y copies of magazine B.
According to the problem, the vendor sold a total of 10 magazines, so we can write the equation:
x + y = 10 ...(1)
The vendor sold magazine A for $5, so the total amount earned from selling magazine A is 5x.
Similarly, the vendor sold magazine B for $8, so the total amount earned from selling magazine B is 8y.
According to the problem, the total amount earned from selling both magazines is $70. So we can write the equation:
5x + 8y = 70 ...(2)
We now have a system of equations (equations 1 and 2) that we can solve simultaneously.
To solve the system, we will use the method of substitution. We will solve equation 1 for x and substitute it into equation 2.
From equation 1, we can write x = 10 - y.
Substituting x = 10 - y into equation 2, we get:
5(10 - y) + 8y = 70
50 - 5y + 8y = 70
3y = 20
y = 20/3
Substituting the value of y back into equation 1, we get:
x + 20/3 = 10
x = 10 - 20/3
x = 30/3 - 20/3
x = 10/3
Therefore, the vendor sold 10/3 copies of magazine A and 20/3 copies of magazine B.