Person A sold his car to Person B at a profit of 20% and B sold it to ...
CP = 100
SP = 120
B:
CP = 120
SP = 132
C:
CP = 132
SP = 120
Mechanic:
CP = 120 + 12 = 132
SP = 143
Loss of A = 143 – 120 = 23
% loss of A = (23 / 100) x 100 = 23%
Person A sold his car to Person B at a profit of 20% and B sold it to ...
D. If Person D paid $12,000 for the car, what was the original price that Person A sold the car for?
Let's start by working backwards. We know that Person D paid $12,000, and the mechanic sold it to them at a profit of 8.33%. Let x be the price that the mechanic paid for the car. Then:
1.0833x = 12000
x = 11075.25
So the mechanic paid $11,075.25 for the car. We also know that the mechanic spent 10% of their purchasing price on repairs, so they spent:
0.1(11075.25) = 1107.525
Now let's work backwards from Person C's sale to the mechanic. We know that Person C sold the car at a loss of 9.09%, so let y be the price that Person C paid for the car. Then:
0.909y = 11075.25 + 1107.525
y = 13333.33
So Person C paid $13,333.33 for the car. We also know that Person B sold the car to Person C at a profit of 10%, so let z be the price that Person B paid for the car. Then:
1.1z = 13333.33
z = 12121.21
So Person B paid $12,121.21 for the car. Finally, we know that Person A sold the car to Person B at a profit of 20%, so let w be the original price that Person A sold the car for. Then:
1.2w = 12121.21
w = 10100.00
Therefore, Person A sold the car for $10,100.00.