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Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)
and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512
bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sector
no.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is
<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in a
contiguous manner?
and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512
bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sector
no.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is
<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in a
contiguous manner?
- a)1281
- b)1282
- c)1283
- d)1284
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Consider a hard disk with 16 recording surfaces (0 −15) having 1...
42797 KB=(42797x 1024 )/512= 85594 sectors
Starting is 1200,9,40 contains total 24 + (6×64) = 408 sectors
Next, 1201, --------, 1283 cylinders contains total 1024×83 = 84992 sec tors
(
each cylinder contains 16 64 1024 sec tors)
Total 408 + 84992= 85400 sec tors
The required cylinder number is 1284 which will contain the last sector of the file
Starting is 1200,9,40 contains total 24 + (6×64) = 408 sectors
Next, 1201, --------, 1283 cylinders contains total 1024×83 = 84992 sec tors
(
each cylinder contains 16 64 1024 sec tors)Total 408 + 84992= 85400 sec tors The required cylinder number is 1284 which will contain the last sector of the fileMost Upvoted Answer
Consider a hard disk with 16 recording surfaces (0 −15) having 1...
To 15) and 256 tracks per surface (0 to 255). Each track contains 512 sectors numbered from 0 to 511. Assume that the starting address of the disk is 0.
1. What is the total number of sectors on the disk?
To calculate the total number of sectors on the disk, we need to multiply the number of recording surfaces, the number of tracks per surface, and the number of sectors per track.
Total number of sectors = Number of recording surfaces * Number of tracks per surface * Number of sectors per track
Total number of sectors = 16 * 256 * 512 = 2,097,152
2. What is the sector address of sector 0 on surface 7, track 128?
To find the sector address, we need to calculate the offset of the sector on the disk.
Sector offset = (Surface number * Number of tracks per surface + Track number) * Number of sectors per track + Sector number
Sector offset = (7 * 256 + 128) * 512 + 0 = 2,211,072
3. What is the sector address of sector 255 on surface 15, track 0?
Using the same formula as in the previous question:
Sector offset = (Surface number * Number of tracks per surface + Track number) * Number of sectors per track + Sector number
Sector offset = (15 * 256 + 0) * 512 + 255 = 2,097,535
1. What is the total number of sectors on the disk?
To calculate the total number of sectors on the disk, we need to multiply the number of recording surfaces, the number of tracks per surface, and the number of sectors per track.
Total number of sectors = Number of recording surfaces * Number of tracks per surface * Number of sectors per track
Total number of sectors = 16 * 256 * 512 = 2,097,152
2. What is the sector address of sector 0 on surface 7, track 128?
To find the sector address, we need to calculate the offset of the sector on the disk.
Sector offset = (Surface number * Number of tracks per surface + Track number) * Number of sectors per track + Sector number
Sector offset = (7 * 256 + 128) * 512 + 0 = 2,211,072
3. What is the sector address of sector 255 on surface 15, track 0?
Using the same formula as in the previous question:
Sector offset = (Surface number * Number of tracks per surface + Track number) * Number of sectors per track + Sector number
Sector offset = (15 * 256 + 0) * 512 + 255 = 2,097,535
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Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer?
Question Description
Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer?.
Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer?.
Solutions for Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a hard disk with 16 recording surfaces (0 −15) having 16384 cylinders (0 −16383)and each cylinder contains 64 sectors (0 − 63) . Data storage capacity in each sector is 512bytes. Data are organized cylinder–wise and the addressing format is <cylinder no., sectorno.>. A file of size 42797 KB is stored in the disk and the starting disk location of the file is<1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in acontiguous manner?a)1281b)1282c)1283d)1284Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice GATE tests.
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