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A sample of moist air at a total pressure of 85 KPa has a dry bulb temperature of 30°C (saturation vapour pressure of water = 4.24 KPa). If the air sample has a relative humidity of 65%, the absolute humidity (in gram) of water vapour per kg of dry air is _______
(Important - Enter only the numerical value in the answer)
Correct answer is between '19,22'. Can you explain this answer?
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A sample of moist air at a total pressure of 85 KPa has a dry bulb tem...
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°C and a wet bulb temperature of 25 °C. Calculate the relative humidity of the air sample.
To calculate the relative humidity, we need to use the concept of wet bulb depression. Wet bulb depression is the difference between the dry bulb temperature and the wet bulb temperature. It represents the amount of evaporation that has occurred from the wet bulb.
Given:
Total pressure (P) = 85 kPa
Dry bulb temperature (Tdb) = 30 °C
Wet bulb temperature (Twb) = 25 °C
First, we need to calculate the saturation vapor pressure at the dry bulb temperature (Pvsat_dry):
Pvsat_dry = 0.611 * exp((17.27 * Tdb) / (Tdb + 237.3))
Next, we need to calculate the saturation vapor pressure at the wet bulb temperature (Pvsat_wet):
Pvsat_wet = 0.611 * exp((17.27 * Twb) / (Twb + 237.3))
The wet bulb depression (WBD) is given by:
WBD = Tdb - Twb
The relative humidity (RH) can be calculated using the following formula:
RH = (Pvsat_wet / Pvsat_dry) * 100
Let's calculate the values:
Pvsat_dry = 0.611 * exp((17.27 * 30) / (30 + 237.3)) = 4.239 kPa
Pvsat_wet = 0.611 * exp((17.27 * 25) / (25 + 237.3)) = 3.173 kPa
WBD = 30 - 25 = 5 °C
RH = (3.173 / 4.239) * 100 = 74.79%
Therefore, the relative humidity of the air sample is approximately 74.79%.
To calculate the relative humidity, we need to use the concept of wet bulb depression. Wet bulb depression is the difference between the dry bulb temperature and the wet bulb temperature. It represents the amount of evaporation that has occurred from the wet bulb.
Given:
Total pressure (P) = 85 kPa
Dry bulb temperature (Tdb) = 30 °C
Wet bulb temperature (Twb) = 25 °C
First, we need to calculate the saturation vapor pressure at the dry bulb temperature (Pvsat_dry):
Pvsat_dry = 0.611 * exp((17.27 * Tdb) / (Tdb + 237.3))
Next, we need to calculate the saturation vapor pressure at the wet bulb temperature (Pvsat_wet):
Pvsat_wet = 0.611 * exp((17.27 * Twb) / (Twb + 237.3))
The wet bulb depression (WBD) is given by:
WBD = Tdb - Twb
The relative humidity (RH) can be calculated using the following formula:
RH = (Pvsat_wet / Pvsat_dry) * 100
Let's calculate the values:
Pvsat_dry = 0.611 * exp((17.27 * 30) / (30 + 237.3)) = 4.239 kPa
Pvsat_wet = 0.611 * exp((17.27 * 25) / (25 + 237.3)) = 3.173 kPa
WBD = 30 - 25 = 5 °C
RH = (3.173 / 4.239) * 100 = 74.79%
Therefore, the relative humidity of the air sample is approximately 74.79%.
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A sample of moist air at a total pressure of 85 KPa has a dry bulb temperature of 30°C(saturation vapour pressure of water = 4.24 KPa). If the air sample has a relative humidity of65%, the absolute humidity (in gram) of water vapour per kg of dry air is _______(Important - Enter only the numerical value in the answer)Correct answer is between '19,22'. Can you explain this answer?
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