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In the following truth table, V = 1 if and only if the input is valid.
  • a)
    Priority encoder
  • b)
    Decoder
  • c)
    Multiplexer
  • d)
    Demultiplexer
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In the following truth table, V = 1 if and only if the input is valid....
Since there are more than one outputs and number of outputs is less than inputs, it is a Priority encoder V=1 when input is valid and for priority encoder it checks first high bit encountered. Except all are having at least one bit high and ‘x’ represents the “don’t care” as we have found a high bit already. So answer is (A).
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In the following truth table, V = 1 if and only if the input is valid.a)Priority encoderb)Decoderc)Multiplexerd)DemultiplexerCorrect answer is option 'A'. Can you explain this answer?
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