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A rod of length L having uniform cross-sectional area A is subjected to a tensile force P as shown in the figure below. If the Young’s modulus of the material varies linearly from E1 to E2 along the length of the rod, the normal stress developed at the section-SS is
  • a)
    P/A
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
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A rod of length L having uniform cross-sectional area A is subjected t...
Stress depends on area.
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A rod of length L having uniform cross-sectional area A is subjected to a tensileforce P as shown in the figure below. If the Young’s modulus of the materialvaries linearly from E1 to E2 along the length of the rod, the normal stressdeveloped at the section-SS isa)P/Ab)c)d)Correct answer is option 'A'. Can you explain this answer?
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A rod of length L having uniform cross-sectional area A is subjected to a tensileforce P as shown in the figure below. If the Young’s modulus of the materialvaries linearly from E1 to E2 along the length of the rod, the normal stressdeveloped at the section-SS isa)P/Ab)c)d)Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A rod of length L having uniform cross-sectional area A is subjected to a tensileforce P as shown in the figure below. If the Young’s modulus of the materialvaries linearly from E1 to E2 along the length of the rod, the normal stressdeveloped at the section-SS isa)P/Ab)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rod of length L having uniform cross-sectional area A is subjected to a tensileforce P as shown in the figure below. If the Young’s modulus of the materialvaries linearly from E1 to E2 along the length of the rod, the normal stressdeveloped at the section-SS isa)P/Ab)c)d)Correct answer is option 'A'. Can you explain this answer?.
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