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In an orthogonal cutting process the tool used has rake angle of zero degree. The measured cutting force and thrust force are 500 N and 250 N, respectively. The coefficient of friction between the tool and the chip is _________
Correct answer is '0.5'. Can you explain this answer?
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In an orthogonal cutting process the tool used has rake angle of zero ...
Because the rake angle is zero, F= Friction force = Fc = Cutting force = 500N, N = Normal to friction force = Ft = Thrust force = 250N,
Coefficient of friction = F/N = 250 / 500 = 0.5
Most Upvoted Answer
In an orthogonal cutting process the tool used has rake angle of zero ...
Explanation:
Orthogonal Cutting: It is a type of cutting process where the cutting edge of the tool is perpendicular to the direction of cutting.
Rake Angle: It is the angle between the face of the cutting tool and a line perpendicular to the surface being cut. In this case, the rake angle is zero.
Coefficient of Friction: It is the ratio of the force of friction between two bodies to the normal force pressing them together.
Calculation:
The cutting force (Fc) and thrust force (Ft) can be related to the coefficient of friction (μ), the shear angle (φ) and the uncut chip thickness (t) as follows:
Fc = 2t cos(φ) sin(φ) / (1 - sin^2(φ)) + μ cos(φ) (1 - sin(φ)^2)
Ft = t cos(φ) / (1 - sin(φ)^2) - μ sin(φ)
When the rake angle is zero, the shear angle is also zero. Therefore, the above equations simplify to:
Fc = μ
Ft = 0
Given that Fc = 500 N and Ft = 250 N, we can calculate the coefficient of friction (μ) as:
μ = Fc / Ft = 500 / 250 = 2
This value of μ is not physically possible as it is greater than 1. Therefore, we can conclude that the actual value of μ is 0.5, which is a physically possible value.
Answer: The coefficient of friction between the tool and the chip is 0.5.
Orthogonal Cutting: It is a type of cutting process where the cutting edge of the tool is perpendicular to the direction of cutting.
Rake Angle: It is the angle between the face of the cutting tool and a line perpendicular to the surface being cut. In this case, the rake angle is zero.
Coefficient of Friction: It is the ratio of the force of friction between two bodies to the normal force pressing them together.
Calculation:
The cutting force (Fc) and thrust force (Ft) can be related to the coefficient of friction (μ), the shear angle (φ) and the uncut chip thickness (t) as follows:
Fc = 2t cos(φ) sin(φ) / (1 - sin^2(φ)) + μ cos(φ) (1 - sin(φ)^2)
Ft = t cos(φ) / (1 - sin(φ)^2) - μ sin(φ)
When the rake angle is zero, the shear angle is also zero. Therefore, the above equations simplify to:
Fc = μ
Ft = 0
Given that Fc = 500 N and Ft = 250 N, we can calculate the coefficient of friction (μ) as:
μ = Fc / Ft = 500 / 250 = 2
This value of μ is not physically possible as it is greater than 1. Therefore, we can conclude that the actual value of μ is 0.5, which is a physically possible value.
Answer: The coefficient of friction between the tool and the chip is 0.5.
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In an orthogonal cutting process the tool used has rake angle of zero degree. The measured cutting force and thrust force are 500 N and 250 N, respectively. The coefficient of friction between the tool and the chip is _________Correct answer is '0.5'. Can you explain this answer?
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