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Q. Consider the function f(x) = 2x3 -3x2 in the domain [-1, 2]. The global minimum of f(x) is ____
(Important - Enter only the numerical value in the answer)
    Correct answer is '-5'. Can you explain this answer?
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    Q.36 to 65 (Two marks Questions)Q.Consider the function f(x) = 2x3-3x2...
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    Q.36 to 65 (Two marks Questions)Q.Consider the function f(x) = 2x3-3x2...
    Global Minimum of f(x) = 2x^3 - 3x^2 in the domain [-1, 2]

    To find the global minimum of the given function f(x) = 2x^3 - 3x^2 in the domain [-1, 2], we need to analyze the critical points and endpoints of the function within the given domain.


    1. Finding the critical points:



    To find the critical points, we need to find the values of x where the derivative of the function is equal to zero or undefined.

    The derivative of f(x) is obtained by differentiating each term of the function with respect to x:

    f'(x) = d/dx (2x^3) - d/dx (3x^2)
    = 6x^2 - 6x

    Next, we set f'(x) = 0 and solve for x:

    6x^2 - 6x = 0
    6x(x - 1) = 0

    So, the critical points are x = 0 and x = 1.


    1. Finding the endpoints:



    The given domain is [-1, 2], which means we need to evaluate the function at x = -1 and x = 2 as well.

    f(-1) = 2(-1)^3 - 3(-1)^2
    = -2 - 3
    = -5

    f(2) = 2(2)^3 - 3(2)^2
    = 16 - 12
    = 4


    1. Comparing the values:



    Now, we compare the values of the critical points and endpoints to find the global minimum.

    f(0) = 2(0)^3 - 3(0)^2
    = 0

    f(1) = 2(1)^3 - 3(1)^2
    = 2 - 3
    = -1

    We can see that the minimum value of f(x) within the given domain is -5, which occurs at x = -1.

    Therefore, the global minimum of f(x) = 2x^3 - 3x^2 in the domain [-1, 2] is -5.
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    Q.36 to 65 (Two marks Questions)Q.Consider the function f(x) = 2x3-3x2 in the domain [-1, 2]. The global minimum of f(x) is ____(Important - Enter only the numerical value in the answer)Correct answer is '-5'. Can you explain this answer?
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