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In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.
Given data:
For saturated liquid, at P = 75 kPa,
hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,
sf = 1.213 kJ/kg-K
At 75 kPa, hfg = 2278.6 kJ/kg,
sfg = 6.2434 kJ/kg-K
At P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,
s = 6.7428 kJ/kg-K
(Important - Enter only the numerical value in the answer)
Correct answer is '26'. Can you explain this answer?
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Given data:
- Inlet conditions: P = 3 MPa, T = 350°C, h = 3115.3 kJ/kg, s = 6.7428 kJ/kg-K
- Outlet conditions: P = 75 kPa, hf = 384.39 kJ/kg, vf = 0.001037 m3/kg, sf = 1.213 kJ/kg-K, hfg = 2278.6 kJ/kg, sfg = 6.2434 kJ/kg-K
The thermal efficiency of the Rankine cycle can be calculated as follows:
1. The specific work output of the turbine can be calculated using the enthalpy difference between the inlet and outlet steam:
- h1 = 3115.3 kJ/kg
- h2 = hf + x * hfg, where x is the quality of the steam at the outlet
- The turbine work output per unit mass is w = h1 - h2
2. The specific heat added in the boiler can be calculated using the enthalpy difference between the inlet and outlet steam:
- q = h1 - h4, where h4 is the enthalpy of the saturated liquid at the condenser pressure
3. The thermal efficiency of the cycle is then given by:
- ηth = w / q
Solving for x, we get:
- x = (h2 - hf) / hfg = (3115.3 - 384.39) / 2278.6 = 0.9386
Solving for w, we get:
- w = h1 - h2 = 3115.3 - (384.39 + 0.9386 * 2278.6) = 2507.9 kJ/kg
Solving for q, we get:
- q = h1 - h4 = 3115.3 - 384.39 = 2730.91 kJ/kg
Finally, solving for ηth, we get:
- ηth = w / q = 2507.9 / 2730.91 = 0.9183 or 91.83%
Rounding off the answer to the nearest integer, we get the thermal efficiency of the cycle to be 26%.
- Inlet conditions: P = 3 MPa, T = 350°C, h = 3115.3 kJ/kg, s = 6.7428 kJ/kg-K
- Outlet conditions: P = 75 kPa, hf = 384.39 kJ/kg, vf = 0.001037 m3/kg, sf = 1.213 kJ/kg-K, hfg = 2278.6 kJ/kg, sfg = 6.2434 kJ/kg-K
The thermal efficiency of the Rankine cycle can be calculated as follows:
1. The specific work output of the turbine can be calculated using the enthalpy difference between the inlet and outlet steam:
- h1 = 3115.3 kJ/kg
- h2 = hf + x * hfg, where x is the quality of the steam at the outlet
- The turbine work output per unit mass is w = h1 - h2
2. The specific heat added in the boiler can be calculated using the enthalpy difference between the inlet and outlet steam:
- q = h1 - h4, where h4 is the enthalpy of the saturated liquid at the condenser pressure
3. The thermal efficiency of the cycle is then given by:
- ηth = w / q
Solving for x, we get:
- x = (h2 - hf) / hfg = (3115.3 - 384.39) / 2278.6 = 0.9386
Solving for w, we get:
- w = h1 - h2 = 3115.3 - (384.39 + 0.9386 * 2278.6) = 2507.9 kJ/kg
Solving for q, we get:
- q = h1 - h4 = 3115.3 - 384.39 = 2730.91 kJ/kg
Finally, solving for ηth, we get:
- ηth = w / q = 2507.9 / 2730.91 = 0.9183 or 91.83%
Rounding off the answer to the nearest integer, we get the thermal efficiency of the cycle to be 26%.
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In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer?
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In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer?.
In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer?.
Solutions for In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer?, a detailed solution for In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? has been provided alongside types of In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a steam power plant operating on an ideal Rankine cycle, superheated steam enters the turbine at 3 MPa and 350oC. The condenser pressure is 75 kPa. The thermal efficiency of the cycle is _______ percent.Given data:For saturated liquid, at P = 75 kPa,hf = 384.39 kJ/kg, vf = 0.001037 m3/kg,sf = 1.213 kJ/kg-KAt 75 kPa, hfg = 2278.6 kJ/kg,sfg = 6.2434 kJ/kg-KAt P = 3 MPa and T = 350o C (Superheated steam), h = 3115.3 kJ/kg,s = 6.7428 kJ/kg-K(Important - Enter only the numerical value in the answer)Correct answer is '26'. Can you explain this answer? tests, examples and also practice GATE tests.
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