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During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP at anode, H2 gas liberated at cathode is?
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During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP ...
Electrolysis of Aqueous NAOH
4g of O2 gas is liberated at NTP at the anode
H2 gas liberated at the cathode is
Conclusion
- Electrolysis is a process in which an electric current is passed through an electrolyte to produce a chemical reaction.
- Aqueous NAOH is an electrolyte that contains dissolved sodium hydroxide in water.
- During electrolysis of aqueous NAOH, the electric current is passed through the electrolyte, and the chemical reaction takes place at the anode and cathode.
4g of O2 gas is liberated at NTP at the anode
- The anode is the positively charged electrode, and it is where oxidation takes place.
- The oxidation reaction at the anode during electrolysis of aqueous NAOH is:
- From the above reaction, it is clear that oxygen gas is liberated at the anode.
- The amount of oxygen gas liberated can be calculated using the formula:
- At NTP (Normal Temperature and Pressure), the volume of 1 mole of gas is 22.4 L.
- Therefore, the volume of 4g of oxygen gas at NTP can be calculated using the formula:
NaOH → Na+ + OH-
2OH- → 1/2O2 + H2O + 2e-
n = m/M
where n is the number of moles of oxygen gas, m is the mass of oxygen gas, and M is the molar mass of oxygen gas.
V = n x 22.4
where V is the volume of oxygen gas and n is the number of moles of oxygen gas.
H2 gas liberated at the cathode is
- The cathode is the negatively charged electrode, and it is where reduction takes place.
- The reduction reaction at the cathode during electrolysis of aqueous NAOH is:
- From the above reaction, it is clear that hydrogen gas is liberated at the cathode.
- The amount of hydrogen gas liberated can be calculated using the same formula as for oxygen gas.
2H2O + 2e- → H2 + 2OH-
Conclusion
- During electrolysis of aqueous NAOH, oxygen gas is liberated at the anode, and hydrogen gas is liberated at the cathode.
- The amount of gas liberated can be calculated using the formula n = m/M and V = n x 22.4 at NTP.
- Electrolysis is an important process used in various industrial applications such as the production of metals, cleaning of metals, and electroplating of metals.
Community Answer
During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP ...
8g ofH2 gas is liberated at cathode
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During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP at anode, H2 gas liberated at cathode is?
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During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP at anode, H2 gas liberated at cathode is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP at anode, H2 gas liberated at cathode is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During electrolysis of aqueous NAOH ,4g of O2 gas is liberated at NTP at anode, H2 gas liberated at cathode is?.
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