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Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (Given Vapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)
- a)Not enough information is given to make a prediction.
- b)The vapour will contain a higher percentage of benzene.
- c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.
- d)The vapour will contain equal amounts of benzene and toluene.
Correct answer is option 'B'. Can you explain this answer?
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Which of the following statements about the composition of the vapour ...
Due to high partial vapour pressure of Benzene as compare to that of toluene so the mole fraction of Benzene will be higher than that of toluene. As a result the vapour will contain a higher percentage of
Benzene.
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Which of the following statements about the composition of the vapour ...
Explanation:
Given information:
- Ideal 1:1 molar mixture of benzene and toluene
- Temperature is constant at 25C
- Vapour Pressure Data at 25C: Benzene = 12.8kPa, toluene = 3.85kPa
To answer this question, we need to consider Raoult's law, which states that the partial pressure of each component in an ideal mixture is proportional to its mole fraction in the mixture. In other words, the more molecules of a component present in the mixture, the higher its partial pressure in the vapour phase.
Using the vapour pressure data given, we can calculate the mole fractions of benzene and toluene in the vapour phase using the following equation:
Mole fraction of benzene = Partial pressure of benzene / Total vapour pressure
Mole fraction of toluene = Partial pressure of toluene / Total vapour pressure
Total vapour pressure = Vapour pressure of benzene + Vapour pressure of toluene
= 12.8kPa + 3.85kPa
= 16.65kPa
Mole fraction of benzene = 12.8kPa / 16.65kPa
= 0.769
Mole fraction of toluene = 3.85kPa / 16.65kPa
= 0.231
Therefore, the vapour will contain a higher percentage of benzene, as its mole fraction in the vapour phase is higher than that of toluene.
Answer: Option B
Given information:
- Ideal 1:1 molar mixture of benzene and toluene
- Temperature is constant at 25C
- Vapour Pressure Data at 25C: Benzene = 12.8kPa, toluene = 3.85kPa
To answer this question, we need to consider Raoult's law, which states that the partial pressure of each component in an ideal mixture is proportional to its mole fraction in the mixture. In other words, the more molecules of a component present in the mixture, the higher its partial pressure in the vapour phase.
Using the vapour pressure data given, we can calculate the mole fractions of benzene and toluene in the vapour phase using the following equation:
Mole fraction of benzene = Partial pressure of benzene / Total vapour pressure
Mole fraction of toluene = Partial pressure of toluene / Total vapour pressure
Total vapour pressure = Vapour pressure of benzene + Vapour pressure of toluene
= 12.8kPa + 3.85kPa
= 16.65kPa
Mole fraction of benzene = 12.8kPa / 16.65kPa
= 0.769
Mole fraction of toluene = 3.85kPa / 16.65kPa
= 0.231
Therefore, the vapour will contain a higher percentage of benzene, as its mole fraction in the vapour phase is higher than that of toluene.
Answer: Option B
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Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer?
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Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer?.
Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statements about the composition of the vapour over an ideal 1 : 1 molarmixture of benzene and toluene is correct ? Assume that the temperature is constant at 25°C. (GivenVapour Pressure Data at 25ºC, Benzene = 12.8kPa, toluene = 3.85kPa)a)Not enough information is given to make a prediction.b)The vapour will contain a higher percentage of benzene.c)The vapour will contain a higher percentage of toluene.The vapour will contain a higher percentage of toluene.d)The vapour will contain equal amounts of benzene and toluene.Correct answer is option 'B'. Can you explain this answer?.
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