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In an electromagnetic wave in free space the root meansquare value of the electric field is Erms = 6V/m. Thepeak value of the magnetic field is :-
  • a)
    2.83 × 10–8 T
  • b)
    0.70 × 10–8 T
  • c)
    4.23 × 10–8 T
  • d)
    1.41 × 10–8 T
Correct answer is option 'A'. Can you explain this answer?
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In an electromagnetic wave in free space the root meansquare value of ...
Given:
Root mean square value of electric field, Erms = 6V/m

To find:
Peak value of the magnetic field

Solution:

The relationship between the electric field (E) and magnetic field (B) in an electromagnetic wave is given by the equation:

E = cB

Where:
E is the electric field
B is the magnetic field
c is the speed of light in vacuum (3 x 10^8 m/s)

Step 1: Convert the given electric field value to the SI unit.

Erms = 6V/m

Since the electric field is given in volts per meter (V/m), it is already in SI units.

Step 2: Substitute the electric field value into the equation to find the magnetic field.

Erms = cB

B = Erms / c

B = 6 V/m / (3 x 10^8 m/s)

B = 2 x 10^-8 T

Step 3: Convert the magnetic field value to scientific notation.

2 x 10^-8 T = 2 x 10^-8 T x 10^8 / 10^8

2 x 10^-8 T = 2 x 10^0 T

Final Answer:
The peak value of the magnetic field is 2.0 x 10^0 T, which can be written as 2.0 T.

Therefore, the correct answer is option A) 2.83 x 10^8 T.
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In an electromagnetic wave in free space the root meansquare value of the electric field is Erms = 6V/m. Thepeak value of the magnetic field is :-a)2.83 × 10–8 Tb)0.70 × 10–8 Tc)4.23 × 10–8 Td)1.41 × 10–8 TCorrect answer is option 'A'. Can you explain this answer?
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