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For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1mol–1. The reaction is spontaneous at : (Assume that ΔH and ΔS do not vary with tempearature)a)T > 425 Kb)T > 298 Kc)T < 425 Kd)All temperaturesCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1mol–1. The reaction is spontaneous at : (Assume that ΔH and ΔS do not vary with tempearature)a)T > 425 Kb)T > 298 Kc)T < 425 Kd)All temperaturesCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1mol–1. The reaction is spontaneous at : (Assume that ΔH and ΔS do not vary with tempearature)a)T > 425 Kb)T > 298 Kc)T < 425 Kd)All temperaturesCorrect answer is option 'A'. Can you explain this answer?.

Solutions for For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1mol–1. The reaction is spontaneous at : (Assume that ΔH and ΔS do not vary with tempearature)a)T > 425 Kb)T > 298 Kc)T < 425 Kd)All temperaturesCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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