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It is because of inability of ns2 electrons of the valence shell to participate in bonding that:-
 
  • a)
    Sn2+ is oxidising while Pb4+ is reducing
  • b)
    Sn2+ and Pb2+ are both oxidising and reducing
  • c)
    Sn4+ is reducing while Pb4+ is oxidising
  • d)
    Sn2+ is reducing while Pb4+ is oxidising
Correct answer is option 'D'. Can you explain this answer?
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Explanation:

Valence Shell Configuration:
- Sn (Tin) has a valence shell configuration of 5s2 5p2, while Pb (Lead) has a valence shell configuration of 6s2 6p2.
- The ns2 electrons in the valence shell of these elements are unable to participate in bonding due to poor shielding effects.

Redox Behavior:
- Sn2+ ion has a configuration of 5s0 5p0, which means it has lost its 2 ns2 electrons and is in a reduced state. It tends to gain electrons, making it a reducing agent.
- Pb4+ ion has a configuration of 6s0 6p0, which means it has lost its 4 ns2 electrons and is in an oxidized state. It tends to lose electrons, making it an oxidizing agent.

Explanation of Options:
- Option 'A' is incorrect because Sn2+ is reducing while Pb4+ is oxidizing.
- Option 'B' is incorrect because Sn2+ and Pb2+ do not have the same redox behaviors.
- Option 'C' is incorrect because Sn4+ is oxidizing while Pb4+ is reducing.
- Option 'D' is correct because Sn2+ is reducing while Pb4+ is oxidizing due to their respective electron configurations and redox behaviors.
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It is because of inability of ns2 electrons of the valence shell to participate in bonding that:-a)Sn2+ is oxidising while Pb4+ is reducingb)Sn2+ and Pb2+ are both oxidising and reducingc)Sn4+ is reducing while Pb4+ is oxidisingd)Sn2+ is reducing while Pb4+ is oxidisingCorrect answer is option 'D'. Can you explain this answer?
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It is because of inability of ns2 electrons of the valence shell to participate in bonding that:-a)Sn2+ is oxidising while Pb4+ is reducingb)Sn2+ and Pb2+ are both oxidising and reducingc)Sn4+ is reducing while Pb4+ is oxidisingd)Sn2+ is reducing while Pb4+ is oxidisingCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about It is because of inability of ns2 electrons of the valence shell to participate in bonding that:-a)Sn2+ is oxidising while Pb4+ is reducingb)Sn2+ and Pb2+ are both oxidising and reducingc)Sn4+ is reducing while Pb4+ is oxidisingd)Sn2+ is reducing while Pb4+ is oxidisingCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It is because of inability of ns2 electrons of the valence shell to participate in bonding that:-a)Sn2+ is oxidising while Pb4+ is reducingb)Sn2+ and Pb2+ are both oxidising and reducingc)Sn4+ is reducing while Pb4+ is oxidisingd)Sn2+ is reducing while Pb4+ is oxidisingCorrect answer is option 'D'. Can you explain this answer?.
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