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Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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the GATE exam syllabus. Information about Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Here you can find the meaning of Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Let M be a Turing Machine has G = (g0, g1, q2, q3, q4} a set of states, input alphabets {0, 1}. The tape alphabets are {0,1, B, X, V). The symbol B is used to represent end of input string. The final state is q4. The transistions are as follows:Which of the following is true about M?a)M halts on L having 100 as substringb)M halts on L having 101 as substringc)M halts on L = 0n1n, n ≥ 0d)M halts on L not having 1100 sbstringCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice GATE tests.