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The total number of 3 digit numbers which have two or more consecutive digits identical is:

  • a)
    171

  • b)
    170

  • c)
    90

  • d)
    180

  • e)
    None of these

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The total number of 3 digit numbers which have two or more consecutive...
In each set of 100 numbers, there are 10 numbers whose tens digit and unit digit are same. Again in the same set there are 10 numbers whose hundreds and tens digits are same. But one number in each set of 100 numbers whose Hundreds, Tens and Unit digit are same as 111, 222, 333, 444 etc

Hence, there are exactly (10 + 10 - 1) = 19 numbers in each set of 100 numbers. Further there are 9 such sets of numbers

Therefore such total numbers = 19 × 9 = 171



Alternatively,

9 × 10 × 10 - 9 × 9 × 9 = 900 - 729 = 171
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Most Upvoted Answer
The total number of 3 digit numbers which have two or more consecutive...
Can we do this method too, I just tried it out,
Front to Back, I mean tens to units place common for 0-9 is , 9 because there are hundreds place can't be zero 
This patterns happens tens times, so 9(10)= 90
Back to Front, 
I mean tens to units place common for 0-9 is , 9 because there are hundreds place can't be zero 
This patterns happens tens times, so 9(10)= 90 again
So 2 times 90 is 180 and there is an intersection which is observed, 111, 222, 333... which I call common Front to Back or common Back to Front, and this pattern happens 9 times, so subtract that and we get the answer as 180-9= 171, EduRev please as your team to verify my answer.
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Community Answer
The total number of 3 digit numbers which have two or more consecutive...
Because in every case you will find first two digit same that's why and is 171 
and its consecutive no are 172 173...
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The total number of 3 digit numbers which have two or more consecutive digits identical is:a)171b)170c)90d)180e)None of theseCorrect answer is option 'A'. Can you explain this answer?
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