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Siddhartha has deposited a certain amount in the bank to earn compound interest at 10% per annum. The difference between the interest of the third year and second year on the amount is Rs. 1,10. What amount has Siddhartha deposited?
  • a)
    Rs. 8500
  • b)
    Rs. 10,000
  • c)
    Rs. 9500 
  • d)
    Rs. 11,000
  • e)
    Rs. 12,000
Correct answer is option 'B'. Can you explain this answer?
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To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the amount after time t
P = the principal amount (initial deposit)
r = annual interest rate (10%)
n = number of times interest is compounded per year
t = number of years

We are given that the difference between the interest of the third year and the second year is Rs. 1,10. Let's assume that the principal amount deposited by Siddhartha is x.

To find the interest for the third year, we can calculate the amount after three years using the formula:

A = x(1 + 0.10/1)^(1*3)
A = x(1.10)^3
A = 1.331x

To find the interest for the second year, we can calculate the amount after two years using the formula:

A = x(1 + 0.10/1)^(1*2)
A = x(1.10)^2
A = 1.21x

Now we can find the difference between the interest of the third year and the second year:

1.331x - 1.21x = Rs. 1,10

0.121x = Rs. 1,10

x = Rs. 1,10 / 0.121

x ≈ Rs. 9,090.91

Therefore, Siddhartha has deposited approximately Rs. 9,090.91 in the bank.
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Siddhartha has deposited a certain amount in the bank to earn compound interest at 10% per annum. The difference between the interest of the third year and second year on the amount is Rs. 1,10. What amount has Siddhartha deposited?a)Rs. 8500b)Rs. 10,000c)Rs. 9500d)Rs. 11,000e)Rs. 12,000Correct answer is option 'B'. Can you explain this answer?
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