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Assume that ‘e’ is the number of edges and n is the number of vertices. The number of non-isomorphic graphs possible with n-vertices such that graph is 3-regular graph and e = 2n – 3 are .
    Correct answer is '2'. Can you explain this answer?
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    Assume that ‘e’ is the number of edges and n is the number...
    For 3- regular: 3n=2.e
    Given e=2n-3, substitute in above equation.
     3n= 2.(2n-3)
     3n = 4n-6
     n =6
     The number of vertices =6.
    n=6  e=2n-3=9
     Number of 3- regular graphs with 6 vertices and 9 edges are 2.

    Both graphs are non –isomorphic but 3 –regular graphs.
     Two graphs are possible.
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    Assume that ‘e’ is the number of edges and n is the number of vertices. The number of non-isomorphic graphs possible with n-vertices such that graph is 3-regular graph and e = 2n – 3 are .Correct answer is '2'. Can you explain this answer?
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