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Consider the following three concurrent processes.

Initially A = 3 , B = 0
Q. What is the minimum number of 1’s printed by the execution of the above processes?
    Correct answer is '0'. Can you explain this answer?
    Verified Answer
    Consider the following three concurrent processes.Initially A = 3 , B ...
    I. A = 3, B = 0
    First process – 1 execute three times and process – 1 is blocked (A=0, B=3).
    II. Process – 3 executes next three times and process – 3 is blocked (A=0,B=0).
    III. Process – 2 executes last then it will be blocked by executing P(B) first time.
     No. ‘1’ is printed by the execution of three processes and all are blocked
    Number of 1’s printed = 0.
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    Consider the following three concurrent processes.Initially A = 3 , B = 0Q. What is the minimum number of 1’s printed by the execution of the above processes?Correct answer is '0'. Can you explain this answer?
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