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The Fourier transform of a signal h(t) is H(jω) = (2 cosω) (sin2ω)/ω. The value of
h(0) is
h(0) is
- a)1/4
- b)1/2
- c)1
- d)2
Correct answer is option 'C'. Can you explain this answer?
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The Fourier transform of a signal h(t) is H(jω) = (2 cosω)...
We know that inverse Fourier transform of sin c function is a rectangular function.
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The Fourier transform of a signal h(t) is H(jω) = (2 cosω)...
Ω), where ω is the frequency domain variable. The Fourier transform is a mathematical transformation that converts a signal from the time domain to the frequency domain. In the frequency domain, the signal is represented as a sum of sinusoidal components with different frequencies, amplitudes, and phases.
The Fourier transform is defined as:
H(jω) = ∫h(t)e^(-jωt)dt
where j = √(-1) is the imaginary unit, ω is the angular frequency in radians per second, and the integral is taken over all time t.
The Fourier transform is a complex function of ω, which means it has both real and imaginary components. The magnitude of the Fourier transform, |H(jω)|, represents the amplitude of the sinusoidal components at each frequency, while the phase of the Fourier transform, arg(H(jω)), represents the phase shift of each component.
The inverse Fourier transform is used to convert the signal back from the frequency domain to the time domain:
h(t) = (1/2π) ∫H(jω)e^(jωt)dω
where the integral is taken over all frequencies ω. The inverse Fourier transform is also a complex function of time t, and it can be used to reconstruct the original signal from its frequency components.
The Fourier transform is defined as:
H(jω) = ∫h(t)e^(-jωt)dt
where j = √(-1) is the imaginary unit, ω is the angular frequency in radians per second, and the integral is taken over all time t.
The Fourier transform is a complex function of ω, which means it has both real and imaginary components. The magnitude of the Fourier transform, |H(jω)|, represents the amplitude of the sinusoidal components at each frequency, while the phase of the Fourier transform, arg(H(jω)), represents the phase shift of each component.
The inverse Fourier transform is used to convert the signal back from the frequency domain to the time domain:
h(t) = (1/2π) ∫H(jω)e^(jωt)dω
where the integral is taken over all frequencies ω. The inverse Fourier transform is also a complex function of time t, and it can be used to reconstruct the original signal from its frequency components.
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The Fourier transform of a signal h(t) is H(jω) = (2 cosω) (sin2ω)/ω. The value ofh(0) isa)1/4b)1/2c)1d)2Correct answer is option 'C'. Can you explain this answer?
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