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Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.
Correct answer is '8'. Can you explain this answer?
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Verified Answer
Find how much disk space (in surfaces) will be required to store 300,0...
Each sector can hold 4 logical records.
The required number of sectors is 303,150/4 = 75,788 sectors
= 75,788/96 tracks = 790 track
= 790/110 = 8 surfaces.
The required number of sectors is 303,150/4 = 75,788 sectors
= 75,788/96 tracks = 790 track
= 790/110 = 8 surfaces.
Most Upvoted Answer
Find how much disk space (in surfaces) will be required to store 300,0...
Solution:
Given:
Number of logical records=300,000
Logical record size=120 Bytes
Sector size=512 Bytes
Number of sectors/track=96
Number of tracks/surface=110
Number of usable surfaces=8
To find:
Disk space required to store 300,000 120-byte logical records.
Approach:
We can calculate the disk space required to store the given logical records using the below formula:
Disk space required = (Number of logical records) * (Logical record size) / (Sector size)
Once we calculate the disk space required for one surface, we can multiply it with the number of usable surfaces to get the total disk space required.
Calculation:
Disk space required for one logical record=120/512=0.234375 sectors
Disk space required for 300,000 logical records=(300,000*120)/512=70,312.5 sectors
Total number of sectors per surface:
=Number of sectors/track * Number of tracks/surface
=96 * 110
=10,560 sectors
Number of logical records that can be stored per surface:
=Number of sectors/surface/Disk space required for one logical record
=10,560/0.234375
=45,000 logical records
Disk space required per surface:
=Number of logical records that can be stored per surface * Disk space required for one logical record
=45,000 * 0.234375
=10,546.875 sectors
Total disk space required:
=Disk space required per surface * Number of usable surfaces
=10,546.875 * 8
=84,375 sectors
Therefore, the disk space required to store 300,000 120-byte logical records on a fixed sector disk with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces is 84,375 sectors.
Given:
Number of logical records=300,000
Logical record size=120 Bytes
Sector size=512 Bytes
Number of sectors/track=96
Number of tracks/surface=110
Number of usable surfaces=8
To find:
Disk space required to store 300,000 120-byte logical records.
Approach:
We can calculate the disk space required to store the given logical records using the below formula:
Disk space required = (Number of logical records) * (Logical record size) / (Sector size)
Once we calculate the disk space required for one surface, we can multiply it with the number of usable surfaces to get the total disk space required.
Calculation:
Disk space required for one logical record=120/512=0.234375 sectors
Disk space required for 300,000 logical records=(300,000*120)/512=70,312.5 sectors
Total number of sectors per surface:
=Number of sectors/track * Number of tracks/surface
=96 * 110
=10,560 sectors
Number of logical records that can be stored per surface:
=Number of sectors/surface/Disk space required for one logical record
=10,560/0.234375
=45,000 logical records
Disk space required per surface:
=Number of logical records that can be stored per surface * Disk space required for one logical record
=45,000 * 0.234375
=10,546.875 sectors
Total disk space required:
=Disk space required per surface * Number of usable surfaces
=10,546.875 * 8
=84,375 sectors
Therefore, the disk space required to store 300,000 120-byte logical records on a fixed sector disk with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces is 84,375 sectors.
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Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer?
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Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer?.
Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find how much disk space (in surfaces) will be required to store 300,000 120-byte logical records, if the disk is fixed sector with 512 bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces. Ignore any file header records and track indices and assume that records cannot span two sectors.Correct answer is '8'. Can you explain this answer?.
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