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Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations
I. x2+15x+56=0
II. y2-23y+132=0
- a)If x>y
- b)If x≥y
- c)If x<y
- d)If x≤y
- e)If x=y or the relationship cannot be established.
Correct answer is option 'C'. Can you explain this answer?
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Directions (6-10): In the following questions, two equations numbered ...
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Directions (6-10): In the following questions, two equations numbered ...
6.
I. x^2 + 15x + 56 = 0
(x+7)(x+8)=0
x=-7, -8
II. y^2 -23y + 132 = 0
(y-11)(y-12)=0
y=11, 12
From the given options, the only common solution is (x=-8, y=12). Hence, option D is correct.
7.
I. x^2 - 5x - 6 = 0
(x-6)(x+1)=0
x=6, -1
II. y^2 + 11y + 18 = 0
(y+2)(y+9)=0
y=-2, -9
From the given options, the only common solution is (x=-1, y=-9). Hence, option B is correct.
8.
I. x^2 - 2x - 15 = 0
(x-5)(x+3)=0
x=5, -3
II. y^2 - 6y + 8 = 0
(y-4)(y-2)=0
y=4, 2
From the given options, the only common solution is (x=5, y=2). Hence, option A is correct.
9.
I. x^2 - 6x + 8 = 0
(x-4)(x-2)=0
x=4, 2
II. y^2 - 5y + 6 = 0
(y-2)(y-3)=0
y=2, 3
From the given options, the only common solution is (x=2, y=2). Hence, option C is correct.
10.
I. x^2 - 10x + 16 = 0
(x-8)(x-2)=0
x=8, 2
II. y^2 - 18y + 77 = 0
(y-11)(y-7)=0
y=11, 7
From the given options, the only common solution is (x=2, y=11). Hence, option B is correct.
I. x^2 + 15x + 56 = 0
(x+7)(x+8)=0
x=-7, -8
II. y^2 -23y + 132 = 0
(y-11)(y-12)=0
y=11, 12
From the given options, the only common solution is (x=-8, y=12). Hence, option D is correct.
7.
I. x^2 - 5x - 6 = 0
(x-6)(x+1)=0
x=6, -1
II. y^2 + 11y + 18 = 0
(y+2)(y+9)=0
y=-2, -9
From the given options, the only common solution is (x=-1, y=-9). Hence, option B is correct.
8.
I. x^2 - 2x - 15 = 0
(x-5)(x+3)=0
x=5, -3
II. y^2 - 6y + 8 = 0
(y-4)(y-2)=0
y=4, 2
From the given options, the only common solution is (x=5, y=2). Hence, option A is correct.
9.
I. x^2 - 6x + 8 = 0
(x-4)(x-2)=0
x=4, 2
II. y^2 - 5y + 6 = 0
(y-2)(y-3)=0
y=2, 3
From the given options, the only common solution is (x=2, y=2). Hence, option C is correct.
10.
I. x^2 - 10x + 16 = 0
(x-8)(x-2)=0
x=8, 2
II. y^2 - 18y + 77 = 0
(y-11)(y-7)=0
y=11, 7
From the given options, the only common solution is (x=2, y=11). Hence, option B is correct.
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Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer?
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Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer?.
Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer?.
Solutions for Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
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Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equationsI. x2+15x+56=0II. y2-23y+132=0a)If x>yb)If x≥yc)If x<yd)If x≤ye)If x=y or the relationship cannot be established.Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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