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A 3 phase, 6 pole star connected alternator revolves at 1000 rpm. The stator has 90 slots and 8 conductor per slot. The flux per pole is 0.05 wb. Calculate phase voltage generated by the machine if the winding factor is 0.96.
  • a)
    1358.56 V
  • b)
    1278.72 V
  • c)
    1456.67 V
  • d)
    1476.75 V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 3 phase, 6 pole star connected alternator revolves at 1000 rpm. The ...
Pole = 6, conductor/slot = 8, flux = 0.05
Winding factor KW = 0.96, speed = 1000 RPM

Number of conductor z = slot × conductor/slot = 90 × 8 = 720

Eph = 4.44 Kc Kd f N = 4.44 × 0.96 × 0.05 × 50 × 120 = 1278.72 V
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Most Upvoted Answer
A 3 phase, 6 pole star connected alternator revolves at 1000 rpm. The ...
Given data:
- Alternator: 3 phase, 6 pole, star connected
- Speed: 1000 rpm
- Stator slots: 90
- Conductors per slot: 8
- Flux per pole: 0.05 Wb
- Winding factor: 0.96

To calculate: Phase voltage generated by the machine

Formula used:
- EMF generated per phase = (4.44 x f x N x P x Z x Φ x KW)/1000
- Where,
- f = frequency = P x S / 120 (in Hz)
- N = Speed of rotation (in rpm)
- P = Number of poles
- S = Number of stator slots
- Z = Number of conductors per slot
- Φ = Flux per pole (in Wb)
- KW = Winding factor

Calculation:
- Frequency f = P x S / 120 = 6 x 1000 / 120 = 50 Hz
- EMF generated per phase = (4.44 x f x N x P x Z x Φ x KW)/1000
= (4.44 x 50 x 1000 x 6 x 8 x 0.05 x 0.96)/1000
= 1278.72 V

Therefore, the phase voltage generated by the machine is 1278.72 V (option B).
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A 3 phase, 6 pole star connected alternator revolves at 1000 rpm. The stator has 90 slots and 8 conductor per slot. The flux per pole is 0.05 wb. Calculate phase voltage generated by the machine if the winding factor is 0.96.a)1358.56 Vb)1278.72 Vc)1456.67 Vd)1476.75 VCorrect answer is option 'B'. Can you explain this answer?
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