The ratio of milk and water in 55 litres of adulterated milk is 7 : 4. How much water must be added to make the mixture’s ratio 7 : 6?a)5 litb)10 litc)15 litd)25 lite)None of the aboveCorrect answer is option 'B'. Can you explain this answer?

Question

The ratio of milk and water in 55 litres of adulterated milk is 7 : 4. How much water must be added to make the mixture&rsquo;s ratio 7 : 6?a)5 litb)10 litc)15 litd)25 lite)None of the aboveCorrect answer is option 'B'. Can you explain this answer?

Answer

Milk quantity in initial mixture : = (7/11) * 55 = 35 liter

and water quantity = (4/11) * 55 = 20 litre

let ' x ' liter water added and so resultant ratio is 7:6

Because Milk quantity is same in both mixture :

so ( 7/13) * (55 + x) = 35

==> x = 10 liter.

Answer

Answer

Pure milk?

Let's start by figuring out how much milk and water are currently in the mixture. We know that the ratio of milk to water is 7:4, which means that for every 7 parts milk there are 4 parts water. This can be written as:

7x + 4x = 55

Where x is a multiplier that we can use to find the actual amount of milk and water. Simplifying this equation:

11x = 55

x = 5

So there are currently 7x5 = 35 litres of milk and 4x5 = 20 litres of water in the mixture.

To make the mixture pure milk, we need to add enough milk to make the ratio 11:0 (since we don't want any water in the mixture). This means we need to add:

11x - 35 = 11(5) - 35 = 10 litres of milk

However, we also need to add an equal amount of water to keep the total volume at 55 litres. So we need to add:

10 litres of water

Therefore, 10 litres of water must be added to make the mixture pure milk.

Answer

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