5 moles of pcl5 are heated in a closed veesel of 5 liter capacity. At ...
To find the value of Kc, we need to use the given information about the moles of PCl5 and the extent of dissociation.
First, we determine the initial concentration of PCl5. Since we have 5 moles of PCl5 in a 5 liter vessel, the initial concentration of PCl5 is 5 moles / 5 liters = 1 M.
Next, we determine the concentration of PCl5 at equilibrium. Since 40% of PCl5 is dissociated, the concentration of PCl5 at equilibrium is 1 M - (1 M * 0.4) = 0.6 M.
Now, let's write the balanced chemical equation for the dissociation of PCl5:
PCl5 ⇌ PCl3 + Cl2
The equilibrium constant expression for this reaction is:
Kc = ([PCl3] * [Cl2]) / [PCl5]
Since we have not been given the concentrations of PCl3 and Cl2, we need to express them in terms of the concentration of PCl5 at equilibrium using stoichiometry.
From the balanced chemical equation, we can see that the molar ratio between PCl5 and both PCl3 and Cl2 is 1:1. Therefore, if x represents the concentration of PCl3 and Cl2 at equilibrium, it will also be equal to 0.6 M.
Now, we can substitute these values into the equilibrium constant expression:
Kc = (0.6 * 0.6) / 0.6 = 0.36 / 0.6 = 0.6
Therefore, the value of Kc for this reaction is 0.6.
The correct answer is not provided in the options given.
5 moles of pcl5 are heated in a closed veesel of 5 liter capacity. At ...
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