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During insertional inactivation following enzyme get inactivate –
  • a)
    LacZ
  • b)
    beta galactosidase
  • c)
    alpha galactosidase
  • d)
    all
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
During insertional inactivation following enzyme get inactivate &ndash...
Insertional Inactivation and Enzyme Inactivation
Insertional inactivation is a process used for identifying bacteria that have taken up foreign DNA. This process involves the insertion of a piece of foreign DNA into a specific gene, resulting in the inactivation of that gene. In the case of lacZ gene, which codes for beta-galactosidase enzyme, the inactivation leads to the loss of enzyme activity.

Explanation of Options
- LacZ: The lacZ gene is the gene that codes for the beta-galactosidase enzyme in bacteria. In insertional inactivation, the lacZ gene is disrupted by the insertion of foreign DNA, leading to the inactivation of the beta-galactosidase enzyme.
- Beta-galactosidase: Beta-galactosidase is the enzyme encoded by the lacZ gene. When the lacZ gene is inactivated through insertional inactivation, the beta-galactosidase enzyme becomes non-functional.
- Alpha-galactosidase: Alpha-galactosidase is not directly involved in insertional inactivation following enzyme inactivation. Therefore, it is not affected by this process.
- All: The correct answer is option 'D' because both lacZ gene and beta-galactosidase enzyme are inactivated during insertional inactivation. Therefore, all the mentioned options are affected in this process.
In conclusion, during insertional inactivation, both the lacZ gene and beta-galactosidase enzyme are inactivated, leading to the loss of enzyme activity. This process is commonly used in molecular biology to study gene function and regulation.
Community Answer
During insertional inactivation following enzyme get inactivate &ndash...
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During insertional inactivation following enzyme get inactivate –a)LacZb)beta galactosidasec)alpha galactosidased)allCorrect answer is option 'D'. Can you explain this answer?
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