A die is rolled three times. The probability that exactly one odd numb...
Probability of getting an odd number in rolling of a die = 3/6 = 1/2.
Now using binomial distribution
P(Exactly one odd number among three outcomes)
View all questions of this test
A die is rolled three times. The probability that exactly one odd numb...
**Solution:**
To solve this problem, we need to find the probability of getting exactly one odd number when a die is rolled three times.
**Step 1: Finding the Sample Space**
When a die is rolled once, the possible outcomes are numbers from 1 to 6. So, when a die is rolled three times, the sample space consists of all possible combinations of three numbers from 1 to 6.
The total number of outcomes in the sample space is given by 6^3 = 216, since each roll has 6 possible outcomes and there are 3 rolls.
**Step 2: Finding the Favorable Outcomes**
To find the favorable outcomes, we need to consider the cases where only one odd number appears in the three rolls.
Case 1: Odd number in the first roll
In this case, we have three options for the odd number (1, 3, or 5), and for each odd number, there are three options for the even numbers (2, 4, or 6) in the remaining two rolls. So, the number of favorable outcomes for this case is 3 * 3 = 9.
Case 2: Odd number in the second roll
Similarly, we have three options for the odd number in the second roll and three options for the even numbers in the first and third rolls. So, the number of favorable outcomes for this case is also 3 * 3 = 9.
Case 3: Odd number in the third roll
Again, we have three options for the odd number in the third roll and three options for the even numbers in the first and second rolls. So, the number of favorable outcomes for this case is 3 * 3 = 9.
**Step 3: Calculating the Probability**
The total number of favorable outcomes is given by 9 + 9 + 9 = 27.
Therefore, the probability of getting exactly one odd number is 27/216 = 3/24 = 3/8.
Hence, the correct answer is option b) 3/8.