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The dry density of aoil sample is 1.6 and optimum water content of 20 %. If the specific gravity of soil particle 2.67 , its degree of saturation will be . Percent. 1) 70 2) 80 3) 90 4) 60?
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The dry density of aoil sample is 1.6 and optimum water content of 20 ...
Calculation of Degree of Saturation

Definition of Degree of Saturation
The degree of saturation of soil is defined as the ratio of the volume of water present in the voids of the soil to the volume of voids of the soil.

Given Data
Dry density of soil sample (γd) = 1.6
Optimum water content (w) = 20%
Specific gravity of soil particle (Gs) = 2.67

Calculation
Volume of voids (Vv) = (1/γd) = (1/1.6) = 0.625 m³/m³

Volume of water present in soil (Vw) = (w/100) × Vv = (20/100) × 0.625 = 0.125 m³/m³

Volume of solids (Vs) = 1 - Vv = 1 - 0.625 = 0.375 m³/m³

Mass of water present in soil (mw) = Vw × γw = 0.125 × 9.81 = 1.226 kN/m³

Mass of soil solids (ms) = Vs × γs = 0.375 × 2.67 × 9.81 = 9.797 kN/m³

Formula
Degree of saturation (S) = (mw/mv) × 100%

Calculation
Mass of water required to saturate the soil (mv) = Vv × γw = 0.625 × 9.81 = 6.127 kN/m³

Degree of saturation (S) = (mw/mv) × 100% = (1.226/6.127) × 100% = 20%

Answer
The degree of saturation of the soil sample is 20%. Therefore, the correct option is 4) 60.
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The dry density of aoil sample is 1.6 and optimum water content of 20 %. If the specific gravity of soil particle 2.67 , its degree of saturation will be . Percent. 1) 70 2) 80 3) 90 4) 60?
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