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The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?
- a)125 km
- b)150 km
- c)140 km
- d)175 km
- e)200 km
Correct answer is option 'B'. Can you explain this answer?
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To solve this problem, we can set up a proportion to find the distance Mr. Ghosh will travel at a speed of 75 kmph.
We are given that at a speed of 50 kmph, Mr. Ghosh can go a distance of 195 kms. Let's denote this distance as D1.
We are also given that at a speed of 75 kmph, Mr. Ghosh needs 30% more fuel than he needs at a speed of 50 kmph. Let's denote the fuel needed at 50 kmph as F1, and the fuel needed at 75 kmph as F2.
So, we can set up the following proportion:
F1/F2 = D1/D2
where D2 is the distance Mr. Ghosh will travel at a speed of 75 kmph.
We are given that F2 is 30% more than F1. This can be written as:
F2 = F1 + 0.3F1
F2 = 1.3F1
Substituting this into the proportion, we have:
F1/1.3F1 = D1/D2
Simplifying the proportion, we get:
1/1.3 = D1/D2
Now, we can substitute the given values into the equation. We know that D1 = 195 kms, so:
1/1.3 = 195/D2
To find D2, we can cross-multiply:
D2 = 195 * 1.3
D2 = 253.5
Therefore, Mr. Ghosh will travel a distance of 253.5 kms at a speed of 75 kmph.
However, none of the given options match this answer. The correct answer should be 253.5 km, but it is not listed as an option.
We are given that at a speed of 50 kmph, Mr. Ghosh can go a distance of 195 kms. Let's denote this distance as D1.
We are also given that at a speed of 75 kmph, Mr. Ghosh needs 30% more fuel than he needs at a speed of 50 kmph. Let's denote the fuel needed at 50 kmph as F1, and the fuel needed at 75 kmph as F2.
So, we can set up the following proportion:
F1/F2 = D1/D2
where D2 is the distance Mr. Ghosh will travel at a speed of 75 kmph.
We are given that F2 is 30% more than F1. This can be written as:
F2 = F1 + 0.3F1
F2 = 1.3F1
Substituting this into the proportion, we have:
F1/1.3F1 = D1/D2
Simplifying the proportion, we get:
1/1.3 = D1/D2
Now, we can substitute the given values into the equation. We know that D1 = 195 kms, so:
1/1.3 = 195/D2
To find D2, we can cross-multiply:
D2 = 195 * 1.3
D2 = 253.5
Therefore, Mr. Ghosh will travel a distance of 253.5 kms at a speed of 75 kmph.
However, none of the given options match this answer. The correct answer should be 253.5 km, but it is not listed as an option.
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The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer?
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The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer?.
The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vehicle of Mr. Ghosh needs 30% more fuel at the speed of 75 kmph than it needs at the speed of 50 kmph. At a speed of 50 kmph, Mr Ghosh can go to a distance of 195 kms. At the speed of 75 kmph, what distance he will travel?a)125 kmb)150 kmc)140 kmd)175 kme)200 kmCorrect answer is option 'B'. Can you explain this answer?.
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