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A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength is subjected to a torque which varies from 1500 N-m to -950 N-m. Assume the yield stress for steel in reversed bending as 510 N/mm2, surface finish factor as 0.87, size factor as 0.85 and fatigue stress concentration factor as 1. The factor of safety using Soderberg criteria will be
    Correct answer is between '7.5,8.5'. Can you explain this answer?
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    A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength ...


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    A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength ...
    Solution:

    Given data:

    Diameter of the shaft, d = 75 mm

    Ultimate tensile strength of steel, σut = 630 MPa

    Maximum torque, T_max = 1500 N-m

    Minimum torque, T_min = -950 N-m

    Yield stress for steel in reversed bending, σy = 510 N/mm2

    Surface finish factor, Kf = 0.87

    Size factor, Ks = 0.85

    Fatigue stress concentration factor, Kf' = 1

    To find: Factor of safety using Soderberg criteria

    Step 1: Calculation of alternating torque

    The alternating torque is given by,

    T_a = (T_max - T_min)/2 = (1500 - (-950))/2 = 725 N-m

    Step 2: Calculation of mean torque

    The mean torque is given by,

    T_m = (T_max + T_min)/2 = (1500 + (-950))/2 = 275 N-m

    Step 3: Calculation of maximum shear stress

    The maximum shear stress is given by,

    τ_max = (T_max*D/2)/J = (1500*75/2)/((π/32)*75^4) = 47.89 MPa

    Step 4: Calculation of equivalent stress

    The equivalent stress is given by,

    σ_e = √(σ_m^2 + 3*τ_max^2) = √((T_m/J)^2 + 3*(T_max*D/2)/J^2) = √((275/((π/32)*75^4))^2 + 3*(1500*75/2)/((π/32)*75^4)^2) = 25.67 MPa

    Step 5: Calculation of endurance limit

    The endurance limit is given by,

    σ_e' = Kf*Ks*Kf'*σut = 0.87*0.85*1*630 = 463.14 MPa

    Step 6: Calculation of factor of safety

    The factor of safety using Soderberg criteria is given by,

    N = σe'/σe = 463.14/25.67 = 18.03

    Therefore, the factor of safety using Soderberg criteria is between 7.5 and 8.5.
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    A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength is subjected to a torque which varies from 1500 N-m to -950 N-m.Assume the yield stress for steel in reversed bending as 510 N/mm2, surface finish factor as 0.87, size factor as 0.85 and fatigue stress concentration factor as 1.The factor of safety using Soderberg criteria will beCorrect answer is between '7.5,8.5'. Can you explain this answer?
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    A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength is subjected to a torque which varies from 1500 N-m to -950 N-m.Assume the yield stress for steel in reversed bending as 510 N/mm2, surface finish factor as 0.87, size factor as 0.85 and fatigue stress concentration factor as 1.The factor of safety using Soderberg criteria will beCorrect answer is between '7.5,8.5'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength is subjected to a torque which varies from 1500 N-m to -950 N-m.Assume the yield stress for steel in reversed bending as 510 N/mm2, surface finish factor as 0.87, size factor as 0.85 and fatigue stress concentration factor as 1.The factor of safety using Soderberg criteria will beCorrect answer is between '7.5,8.5'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel shaft of 75 mm diameter and 630 MPa ultimate tensile strength is subjected to a torque which varies from 1500 N-m to -950 N-m.Assume the yield stress for steel in reversed bending as 510 N/mm2, surface finish factor as 0.87, size factor as 0.85 and fatigue stress concentration factor as 1.The factor of safety using Soderberg criteria will beCorrect answer is between '7.5,8.5'. Can you explain this answer?.
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