To solve this problem, let's first break it down into two parts:

Part 1: Finding the consecutive odd numbers
We are given that the sum of eight consecutive odd numbers is 656. Let's assume that the first odd number in the sequence is 'x'. Since the numbers are consecutive, the second odd number will be 'x + 2', the third will be 'x + 4', and so on. The eighth odd number will be 'x + 14'.

Now, we can form an equation to represent the sum of these consecutive odd numbers:

x + (x + 2) + (x + 4) + (x + 6) + (x + 8) + (x + 10) + (x + 12) + (x + 14) = 656

Simplifying the equation, we get:

8x + 56 = 656

Subtracting 56 from both sides, we get:

8x = 600

Dividing both sides by 8, we get:

x = 75

So, the first odd number in the sequence is 75, and the second largest odd number is the eighth one, which is 75 + 14 = 89.

Part 2: Finding the average of four consecutive even numbers
We are given that the average of four consecutive even numbers is 87. Let's assume that the first even number in the sequence is 'y'. Since the numbers are consecutive, the second even number will be 'y + 2', the third will be 'y + 4', and so on. The fourth even number will be 'y + 6'.

Now, we can form an equation to represent the average of these consecutive even numbers:

(y + y + 2 + y + 4 + y + 6) / 4 = 87

Simplifying the equation, we get:

4y + 12 = 348

Subtracting 12 from both sides, we get:

4y = 336

Dividing both sides by 4, we get:

y = 84

So, the first even number in the sequence is 84, and the second largest even number is the fourth one, which is 84 + 6 = 90.

Finally, we need to find the sum of the smallest odd number (75) and the second largest even number (90):

75 + 90 = 165

Therefore, the correct answer is 165, not 163 as mentioned.