To get 2Ω resistance using only 6Ω resistors, the number of them required isa)2b)3c)4d)6Correct answer is option 'B'. Can you explain this answer?

Question

To get 2&Omega; resistance using only 6&Omega; resistors, the number of them required isa)2b)3c)4d)6Correct answer is option 'B'. Can you explain this answer?

Answer

Three resistors of 2Ω is required to get 6Ω because resultant is more than individual so they all must be connected in series.

Answer

In parallel connection:-
1/R=1/R1+1/R2+.....+1/Rn,
to find n=?,for which R=2 ohm,
1/R=n(1/6),
1/2=n(1/6),
1/2=n/6,
1=n/3,
n=3

Answer

Answer

By using only 6 ohm resistors to get 2 ohm resistances we should connect all the resistors parallel to each other because we know that in parallel the resistance of a resistors becomes half

Answer

See hme jo resistance chahiye 2ohm is less than 6ohm mtb jo bhi connection hu hai is in parallel okhh toh 1/n/6=2

where n=3

Answer

Answer

OPTIONS.b.
By parallel combinations.

Answer

Ans- 3 resistor.

x * 1/6 = 1/2
x = 1/2 * 6
x= 3

Answer

Total number of resistors used in the circuit is 3 in order to get 2 ohms equivalent resistance.

Explanation:

In this case, to get 2 ohm resistance using only 6 ohm resistor, we need to find the number of resistors.

When 3 resistors of 6 ohms are connected in parallel, then the equivalent resistance is given by :

1/R=1/R1+ 1/R2+1/R3

1/R= 1/6 + 1/6 + 1/6

R = 2 ohms

So, total number of resistors used in the circuit is 3 in order to get 2 ohms equivalent resistance.

Answer

4

Answer

3 resistor

Answer

To get 2, you can:

1. Add 1 and 1 together: 1 + 1 = 2.
2. Subtract 0 from 2: 2 - 0 = 2.
3. Multiply 2 by 1: 2 * 1 = 2.
4. Divide 4 by 2: 4 / 2 = 2.
5. Take the square root of 4: √4 = 2.
6. Raise 2 to the power of 1: 2^1 = 2.

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