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The number of bytes required to represent the decimal number 1856357 in packed BCD
(Binary Coded Decimal) form is __________ .
    Correct answer is '4'. Can you explain this answer?
    Verified Answer
    The number of bytes required to represent the decimal number 1856357 i...
    In packed BCD (Binary Coded Decimal) typically encoded two decimal digits within a single
    byte by taking advantage of the fact that four bits are enough to represent the range 0 to 9.
    So, 1856357 is required 4-bytes to stored these BCD digits
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    Most Upvoted Answer
    The number of bytes required to represent the decimal number 1856357 i...
    Number Representation

    In packed BCD (Binary Coded Decimal) representation, each decimal digit is encoded using a 4-bit binary code. This means that each digit from 0 to 9 requires 4 bits to represent in packed BCD form.

    Given Number

    The given decimal number is 1856357. To represent this number in packed BCD form, we need to determine the number of bytes required.

    Calculating the Number of Bytes

    To calculate the number of bytes required, we can follow these steps:

    1. Convert the decimal number to its equivalent binary representation.

    - 1856357 in binary is 111000101001101001101.

    2. Divide the binary representation into groups of 4 bits, starting from the rightmost digit.

    - 1110 0010 1001 1010 0110 1.

    3. Count the number of groups obtained. Each group represents a BCD digit.

    - We have 6 groups, which means we have 6 BCD digits.

    4. Calculate the number of bytes required by dividing the number of groups by 2.

    - Since each byte consists of 2 BCD digits, we divide 6 by 2 to get 3.

    Therefore, the number of bytes required to represent the decimal number 1856357 in packed BCD form is 3.

    Verification

    To verify the answer, we can convert the decimal number to packed BCD form.

    1856357 in packed BCD form is:

    - 0001 1000 0101 0110 0011 0101 0111.

    We can see that there are 7 groups of 4 bits, which means we have 7 BCD digits. Since each byte consists of 2 BCD digits, we have a total of 3 bytes.

    Therefore, the answer is correct, and 3 bytes are required to represent the decimal number 1856357 in packed BCD form.
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    The number of bytes required to represent the decimal number 1856357 i...
    Then what about 4358357?
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    The number of bytes required to represent the decimal number 1856357 in packed BCD(Binary Coded Decimal) form is __________ .Correct answer is '4'. Can you explain this answer?
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