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A 16 Kb (=16,384 bit) memory array is designed as a square with an aspect ratio of one
(number of rows is equal to the number of columns). The minimum number of address lines
needed for the row decoder is ___________________.
(number of rows is equal to the number of columns). The minimum number of address lines
needed for the row decoder is ___________________.
Correct answer is '7'. Can you explain this answer?
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Verified Answer
A 16 Kb (=16,384 bit) memory array is designed as a square with an asp...
Generally the structure of a memory chip = Number of Row × Number of column
= M×N
→ The number of address line required for row decoder is n where M = 2n or
n = log2M
→ As per information given in question : M = N
So M×N = M×M = M2 = 16k = 24×210
M2 = 214
M = 128
→ n = log2128 = 7
= M×N
→ The number of address line required for row decoder is n where M = 2n or
n = log2M
→ As per information given in question : M = N
So M×N = M×M = M2 = 16k = 24×210
M2 = 214 M = 128→ n = log2128 = 7
Most Upvoted Answer
A 16 Kb (=16,384 bit) memory array is designed as a square with an asp...
Understanding the Problem:
We are given a memory array with an aspect ratio of 1, meaning the number of rows is equal to the number of columns. The memory array has a total capacity of 16 Kb, which is equivalent to 16,384 bits. We need to determine the minimum number of address lines required for the row decoder in this memory array.
Solution:
To find the minimum number of address lines needed for the row decoder, we need to consider the total number of rows in the memory array.
Calculating the Number of Rows:
Since the memory array has an aspect ratio of 1, the number of rows is equal to the number of columns. Let's assume the number of rows (or columns) is 'n'.
To calculate the number of rows, we can use the formula:
Total capacity of memory = number of rows * number of columns * bit per cell
Given that the total capacity of memory is 16 Kb and the bit per cell is 1, we can substitute these values into the formula:
16,384 bits = n * n * 1
Simplifying the equation:
16,384 = n^2
Taking the square root of both sides:
n = √16,384
n = 128
Therefore, the number of rows (or columns) in the memory array is 128.
Calculating the Number of Address Lines:
The number of address lines needed for the row decoder is determined by the number of rows in the memory array. We can calculate the number of address lines using the formula:
Number of address lines = log2(number of rows)
Substituting the value of 'n' into the formula:
Number of address lines = log2(128)
Using the property of logarithms, we can rewrite the equation as:
Number of address lines = log2(2^7)
Since log2(2^7) = 7, we can conclude that the minimum number of address lines needed for the row decoder is 7.
Therefore, the correct answer is 7.
We are given a memory array with an aspect ratio of 1, meaning the number of rows is equal to the number of columns. The memory array has a total capacity of 16 Kb, which is equivalent to 16,384 bits. We need to determine the minimum number of address lines required for the row decoder in this memory array.
Solution:
To find the minimum number of address lines needed for the row decoder, we need to consider the total number of rows in the memory array.
Calculating the Number of Rows:
Since the memory array has an aspect ratio of 1, the number of rows is equal to the number of columns. Let's assume the number of rows (or columns) is 'n'.
To calculate the number of rows, we can use the formula:
Total capacity of memory = number of rows * number of columns * bit per cell
Given that the total capacity of memory is 16 Kb and the bit per cell is 1, we can substitute these values into the formula:
16,384 bits = n * n * 1
Simplifying the equation:
16,384 = n^2
Taking the square root of both sides:
n = √16,384
n = 128
Therefore, the number of rows (or columns) in the memory array is 128.
Calculating the Number of Address Lines:
The number of address lines needed for the row decoder is determined by the number of rows in the memory array. We can calculate the number of address lines using the formula:
Number of address lines = log2(number of rows)
Substituting the value of 'n' into the formula:
Number of address lines = log2(128)
Using the property of logarithms, we can rewrite the equation as:
Number of address lines = log2(2^7)
Since log2(2^7) = 7, we can conclude that the minimum number of address lines needed for the row decoder is 7.
Therefore, the correct answer is 7.
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A 16 Kb (=16,384 bit) memory array is designed as a square with an aspect ratio of one(number of rows is equal to the number of columns). The minimum number of address linesneeded for the row decoder is ___________________.Correct answer is '7'. Can you explain this answer?
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