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Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the ground
state irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The threshold
frequency of the material is
state irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The threshold
frequency of the material is
- a)1.6 × 1015 Hz
- b)2.5 × 1015 Hz
- c)4 × 1015 Hz
- d)5 × 1015 Hz
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Monochromatic radiation emitted when electron on hydrogen atom jumps f...
We can use the formula for the stopping potential:
V_stop = hf/e
where V_stop is the stopping potential, h is Planck's constant, f is the frequency of the radiation, and e is the charge of an electron. We know that the radiation is monochromatic and comes from the transition of the electron from the first excited state to the ground state of hydrogen. This means that the frequency of the radiation is given by:
f = (E_2 - E_1)/h
where E_2 is the energy of the ground state of hydrogen and E_1 is the energy of the first excited state. These energies can be calculated using the Rydberg formula:
1/lambda = R*(1/n_1^2 - 1/n_2^2)
where lambda is the wavelength of the radiation, R is the Rydberg constant, and n_1 and n_2 are the initial and final energy levels of the electron. For the transition from the first excited state to the ground state of hydrogen, we have n_1 = 2 and n_2 = 1. Plugging these values into the Rydberg formula and solving for lambda, we get:
lambda = 121.6 nm
Using the speed of light c = lambda*f, we can find the frequency f:
f = c/lambda = 2.47 x 10^15 Hz
Plugging in these values into the formula for the stopping potential and solving for the threshold frequency, we get:
V_stop = (h/e)*f - (phi/e)
where phi is the work function of the photosensitive material. Since the electron is being emitted from the material, we know that its kinetic energy is equal to the stopping potential, so we can rewrite the equation as:
V_stop = (h/e)*(f - f_th)
where f_th is the threshold frequency of the material. Solving for f_th, we get:
f_th = f - (e*V_stop)/h = 1.6 x 10^15 Hz
Therefore, the threshold frequency of the material is 1.6 x 10^15 Hz.
V_stop = hf/e
where V_stop is the stopping potential, h is Planck's constant, f is the frequency of the radiation, and e is the charge of an electron. We know that the radiation is monochromatic and comes from the transition of the electron from the first excited state to the ground state of hydrogen. This means that the frequency of the radiation is given by:
f = (E_2 - E_1)/h
where E_2 is the energy of the ground state of hydrogen and E_1 is the energy of the first excited state. These energies can be calculated using the Rydberg formula:
1/lambda = R*(1/n_1^2 - 1/n_2^2)
where lambda is the wavelength of the radiation, R is the Rydberg constant, and n_1 and n_2 are the initial and final energy levels of the electron. For the transition from the first excited state to the ground state of hydrogen, we have n_1 = 2 and n_2 = 1. Plugging these values into the Rydberg formula and solving for lambda, we get:
lambda = 121.6 nm
Using the speed of light c = lambda*f, we can find the frequency f:
f = c/lambda = 2.47 x 10^15 Hz
Plugging in these values into the formula for the stopping potential and solving for the threshold frequency, we get:
V_stop = (h/e)*f - (phi/e)
where phi is the work function of the photosensitive material. Since the electron is being emitted from the material, we know that its kinetic energy is equal to the stopping potential, so we can rewrite the equation as:
V_stop = (h/e)*(f - f_th)
where f_th is the threshold frequency of the material. Solving for f_th, we get:
f_th = f - (e*V_stop)/h = 1.6 x 10^15 Hz
Therefore, the threshold frequency of the material is 1.6 x 10^15 Hz.
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Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer?
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Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer?.
Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the groundstate irradiates a photosensitive material. The stopping potential is measured do be 3.57 V. The thresholdfrequency of the material isa)1.6 × 1015 Hzb)2.5 × 1015 Hzc)4 × 1015 Hzd)5 × 1015 HzCorrect answer is option 'A'. Can you explain this answer?.
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