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For the circuit shown in figure diode cut in voltage is Vin = 0. T he Ripple voltage to not more than Vrip= 4V.The min load resistance(in k), that can be corrected to the output is____________________Correct answer is between '6.20,6.30'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For the circuit shown in figure diode cut in voltage is Vin = 0. T he Ripple voltage to not more than Vrip= 4V.The min load resistance(in k), that can be corrected to the output is____________________Correct answer is between '6.20,6.30'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the circuit shown in figure diode cut in voltage is Vin = 0. T he Ripple voltage to not more than Vrip= 4V.The min load resistance(in k), that can be corrected to the output is____________________Correct answer is between '6.20,6.30'. Can you explain this answer?.

Solutions for For the circuit shown in figure diode cut in voltage is Vin = 0. T he Ripple voltage to not more than Vrip= 4V.The min load resistance(in k), that can be corrected to the output is____________________Correct answer is between '6.20,6.30'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

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