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Standard enthalpy of vapourisation for water at 100° C is 40.66 kJmol–1. The internal energy ofvapourisation of water at 100°C (in kJmol–1) is(Assume water vapour to behave like an ideal gas)a)+43.76b)+40.66c)+37.56d)–43.76Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Standard enthalpy of vapourisation for water at 100° C is 40.66 kJmol–1. The internal energy ofvapourisation of water at 100°C (in kJmol–1) is(Assume water vapour to behave like an ideal gas)a)+43.76b)+40.66c)+37.56d)–43.76Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Standard enthalpy of vapourisation for water at 100° C is 40.66 kJmol–1. The internal energy ofvapourisation of water at 100°C (in kJmol–1) is(Assume water vapour to behave like an ideal gas)a)+43.76b)+40.66c)+37.56d)–43.76Correct answer is option 'C'. Can you explain this answer?.

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