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What is observed when a solution of potassium iodide is added to silver nitrate solution ?
- a)No reaction takes place
- b)White precipitate of silver iodide is formed
- c)yellow precipitate of Agl is formed
- d)Agl is soluble in water
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What is observed when a solution of potassium iodide is added to silve...
KI(aq) + Pb(NO3)2 (aq) → PbI2(s) + 2KNO3(aq)
The reaction will produce a precipitate of lead iodide . This has a bright yellow colour.
Observation: when you mix the two colourless solutions , a bright yellow cloudiness develops - which is the insoluble lead iodide. This will later settle out as an insoluble precipitate.
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Most Upvoted Answer
What is observed when a solution of potassium iodide is added to silve...
When a solution of potassium iodide is added to silver nitrate solution, the following observations can be made:
Formation of a yellow precipitate
- A yellow precipitate of silver iodide (AgI) is formed. This is due to the reaction between the potassium iodide and silver nitrate solutions. The silver ion (Ag+) from the silver nitrate solution reacts with the iodide ion (I-) from the potassium iodide solution to form solid silver iodide (AgI) which appears as a yellow precipitate.
AgNO3 + KI → AgI + KNO3
Solubility of AgI in water
- Silver iodide is insoluble in water, and therefore appears as a precipitate. Unlike silver chloride and silver bromide, silver iodide is only slightly soluble in ammonia solution.
Selective precipitation
- The formation of the yellow precipitate of AgI is used as a selective precipitation method for the determination of iodide ions in a solution. This method is based on the fact that silver iodide is more insoluble than silver chloride (AgCl) and silver bromide (AgBr), and hence can be easily precipitated out from a solution containing all three halide ions (Cl-, Br-, and I-).
Overall, the addition of potassium iodide to silver nitrate solution results in the formation of a yellow precipitate of silver iodide, which is insoluble in water and can be used for the selective precipitation of iodide ions.
Formation of a yellow precipitate
- A yellow precipitate of silver iodide (AgI) is formed. This is due to the reaction between the potassium iodide and silver nitrate solutions. The silver ion (Ag+) from the silver nitrate solution reacts with the iodide ion (I-) from the potassium iodide solution to form solid silver iodide (AgI) which appears as a yellow precipitate.
AgNO3 + KI → AgI + KNO3
Solubility of AgI in water
- Silver iodide is insoluble in water, and therefore appears as a precipitate. Unlike silver chloride and silver bromide, silver iodide is only slightly soluble in ammonia solution.
Selective precipitation
- The formation of the yellow precipitate of AgI is used as a selective precipitation method for the determination of iodide ions in a solution. This method is based on the fact that silver iodide is more insoluble than silver chloride (AgCl) and silver bromide (AgBr), and hence can be easily precipitated out from a solution containing all three halide ions (Cl-, Br-, and I-).
Overall, the addition of potassium iodide to silver nitrate solution results in the formation of a yellow precipitate of silver iodide, which is insoluble in water and can be used for the selective precipitation of iodide ions.
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What is observed when a solution of potassium iodide is added to silve...
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What is observed when a solution of potassium iodide is added to silver nitrate solution ?a)No reaction takes placeb)White precipitate of silver iodide is formedc)yellow precipitate of Agl is formedd)Agl is soluble in waterCorrect answer is option 'C'. Can you explain this answer?
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What is observed when a solution of potassium iodide is added to silver nitrate solution ?a)No reaction takes placeb)White precipitate of silver iodide is formedc)yellow precipitate of Agl is formedd)Agl is soluble in waterCorrect answer is option 'C'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about What is observed when a solution of potassium iodide is added to silver nitrate solution ?a)No reaction takes placeb)White precipitate of silver iodide is formedc)yellow precipitate of Agl is formedd)Agl is soluble in waterCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is observed when a solution of potassium iodide is added to silver nitrate solution ?a)No reaction takes placeb)White precipitate of silver iodide is formedc)yellow precipitate of Agl is formedd)Agl is soluble in waterCorrect answer is option 'C'. Can you explain this answer?.
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