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Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?
- a)The solution turned red.
- b)Yellow precipitate was formed.
- c)White precipitate was formed.
- d)The reaction mixture became hot.
Correct answer is option 'B'. Can you explain this answer?
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Reema took 5ml of Lead Nitrate solution in a beaker and added approxim...
Observation in the reaction between Lead Nitrate and Potassium Iodide
Introduction:
Reema performed an experiment in which she added Potassium Iodide solution to Lead Nitrate solution. She observed some changes in the solution. This reaction is a classic example of a double displacement reaction.
Observation:
Reema would observe the following upon adding Potassium Iodide solution to Lead Nitrate solution:
- Yellow precipitate was formed
Explanation:
The reaction between Lead Nitrate and Potassium Iodide forms a yellow precipitate of Lead Iodide. The balanced chemical equation for the reaction is:
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
Lead Nitrate is a colorless, transparent, and crystalline solid that dissolves readily in water to form a clear solution. Potassium Iodide is also a white crystalline solid that dissolves in water to form a clear solution. When these two solutions are combined, the following reaction takes place.
Lead Nitrate reacts with Potassium Iodide to form Lead Iodide, which is insoluble in water. The yellow precipitate of Lead Iodide is formed in the reaction mixture.
Conclusion:
Reema would observe a yellow precipitate when she added Potassium Iodide solution to Lead Nitrate solution. This observation confirms that a chemical reaction has taken place between the two solutions.
Introduction:
Reema performed an experiment in which she added Potassium Iodide solution to Lead Nitrate solution. She observed some changes in the solution. This reaction is a classic example of a double displacement reaction.
Observation:
Reema would observe the following upon adding Potassium Iodide solution to Lead Nitrate solution:
- Yellow precipitate was formed
Explanation:
The reaction between Lead Nitrate and Potassium Iodide forms a yellow precipitate of Lead Iodide. The balanced chemical equation for the reaction is:
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
Lead Nitrate is a colorless, transparent, and crystalline solid that dissolves readily in water to form a clear solution. Potassium Iodide is also a white crystalline solid that dissolves in water to form a clear solution. When these two solutions are combined, the following reaction takes place.
Lead Nitrate reacts with Potassium Iodide to form Lead Iodide, which is insoluble in water. The yellow precipitate of Lead Iodide is formed in the reaction mixture.
Conclusion:
Reema would observe a yellow precipitate when she added Potassium Iodide solution to Lead Nitrate solution. This observation confirms that a chemical reaction has taken place between the two solutions.
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Community Answer
Reema took 5ml of Lead Nitrate solution in a beaker and added approxim...
(B) is the correct answer because when Lead nitrate reacts with Potassium Iodide then a yellow precipitate of Lead iodide is formed.
Pb(NO3)2+ KI = PbI(yellow precipitate) + KNO3
Pb(NO3)2+ KI = PbI(yellow precipitate) + KNO3
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Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer?
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Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer?.
Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer?.
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Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?a)The solution turned red.b)Yellow precipitate was formed.c)White precipitate was formed.d)The reaction mixture became hot.Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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