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When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.
Correct answer is between '100,100'. Can you explain this answer?
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Verified Answer
When the voltage across a battery is measured using a d.c. potentiomet...
We use potentiometer to measure unknown voltages (very low) it is a Null type instrument
→ The Galvanometer reads zero when the voltage drop across slide wire and unknown Battery voltages are equal.
→ Given that potentiometer reading as 1.08V i.e., The Battery voltage will be 1.08 volts.
→ Given that potentiometer reading as 1.08V i.e., The Battery voltage will be 1.08 volts.
PMMC reads,
vm = 0.99V.
V = 1.08 - 0.99
V = 0.09 Volts.
vm = 0.99V.
V = 1.08 - 0.99
V = 0.09 Volts.
Most Upvoted Answer
When the voltage across a battery is measured using a d.c. potentiomet...
Calculating Internal Resistance of the Battery:
1. Given Data:
- Voltage measured using d.c. potentiometer: 1.08V
- Voltage measured using PMMC voltmeter: 0.99V
- Resistance of the voltmeter: 1100Ω
2. Calculating Internal Resistance:
- Let the internal resistance of the battery be 'R'.
- The voltage measured by the PMMC voltmeter is the voltage across the combination of the battery and the voltmeter.
- Using voltage divider rule, we can write:
\[0.99 = \frac{R}{R+1100} \times 1.08\]
3. Solving the Equation:
- Solving the above equation, we get:
\[0.99 = \frac{R}{R+1100} \times 1.08\]
\[0.99 = \frac{1.08R}{R+1100}\]
\[0.99(R + 1100) = 1.08R\]
\[0.99R + 1089 = 1.08R\]
\[1.08R - 0.99R = 1089\]
\[0.09R = 1089\]
\[R = \frac{1089}{0.09}\]
\[R = 12100Ω\]
4. Final Answer:
- The internal resistance of the battery is 12100Ω or 12.1 kΩ.
1. Given Data:
- Voltage measured using d.c. potentiometer: 1.08V
- Voltage measured using PMMC voltmeter: 0.99V
- Resistance of the voltmeter: 1100Ω
2. Calculating Internal Resistance:
- Let the internal resistance of the battery be 'R'.
- The voltage measured by the PMMC voltmeter is the voltage across the combination of the battery and the voltmeter.
- Using voltage divider rule, we can write:
\[0.99 = \frac{R}{R+1100} \times 1.08\]
3. Solving the Equation:
- Solving the above equation, we get:
\[0.99 = \frac{R}{R+1100} \times 1.08\]
\[0.99 = \frac{1.08R}{R+1100}\]
\[0.99(R + 1100) = 1.08R\]
\[0.99R + 1089 = 1.08R\]
\[1.08R - 0.99R = 1089\]
\[0.09R = 1089\]
\[R = \frac{1089}{0.09}\]
\[R = 12100Ω\]
4. Final Answer:
- The internal resistance of the battery is 12100Ω or 12.1 kΩ.
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When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer?
Question Description
When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer?.
When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer?.
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When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer?, a detailed solution for When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? has been provided alongside types of When the voltage across a battery is measured using a d.c. potentiometer, the reading shows 1.08V. But when the same voltage is measured using a Permanent Magnet Moving Coil (PMMC) voltmeter, the voltmeter reading shows 0.99V. If the resistance of the voltmeter is 1100Ω, the internal resistance of the battery, in Ω, is _________.Correct answer is between '100,100'. Can you explain this answer? theory, EduRev gives you an
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