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In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If the
base resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage is
base resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage is
- a)1 mV
- b)10 mV
- c)0.1 V
- d)1.0 V
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In a CE transistor amplifier, the audio signal voltage across the coll...
Ω is 8 V. If the base-emitter voltage is 0.7 V, what is the current flowing through the collector?
We can use Ohm's Law to find the current flowing through the collector:
Ic = Vc / Rc
Where Ic is the collector current, Vc is the voltage across the collector resistance, and Rc is the collector resistance.
Substituting the given values, we get:
Ic = 8 V / 2 kΩ = 0.004 A = 4 mA
Now we can use the relationship between the collector current and the base current in a CE transistor amplifier:
Ic = β * Ib
Where β is the transistor's current gain and Ib is the base current.
Assuming a typical value for β of 100, we can solve for Ib:
Ib = Ic / β = 4 mA / 100 = 0.04 mA = 40 μA
Finally, we can use the base-emitter voltage and the base current to find the emitter current:
Ie = (Vbe - 0.7 V) / Re
Where Ie is the emitter current and Re is the emitter resistance.
Assuming a typical value for the base-emitter voltage of 0.7 V and a value for Re of 1 kΩ, we get:
Ie = (0.7 V - 0.7 V) / 1 kΩ = 0 A
This means that all of the collector current flows through the load resistor and none of it flows through the emitter resistor.
We can use Ohm's Law to find the current flowing through the collector:
Ic = Vc / Rc
Where Ic is the collector current, Vc is the voltage across the collector resistance, and Rc is the collector resistance.
Substituting the given values, we get:
Ic = 8 V / 2 kΩ = 0.004 A = 4 mA
Now we can use the relationship between the collector current and the base current in a CE transistor amplifier:
Ic = β * Ib
Where β is the transistor's current gain and Ib is the base current.
Assuming a typical value for β of 100, we can solve for Ib:
Ib = Ic / β = 4 mA / 100 = 0.04 mA = 40 μA
Finally, we can use the base-emitter voltage and the base current to find the emitter current:
Ie = (Vbe - 0.7 V) / Re
Where Ie is the emitter current and Re is the emitter resistance.
Assuming a typical value for the base-emitter voltage of 0.7 V and a value for Re of 1 kΩ, we get:
Ie = (0.7 V - 0.7 V) / 1 kΩ = 0 A
This means that all of the collector current flows through the load resistor and none of it flows through the emitter resistor.
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Community Answer
In a CE transistor amplifier, the audio signal voltage across the coll...
Option b is correct because the current amplification of the transisistor is 100 and base resistance is 1 John
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In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer?
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In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer?.
In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. If thebase resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage isa)1 mVb)10 mVc)0.1 Vd)1.0 VCorrect answer is option 'B'. Can you explain this answer?.
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