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In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer?.

Solutions for In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II isa)1/3b)1/2c)1d)2Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice GATE tests.