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In a steady and incompressible flow of a fluid (density = 1.25 kg m-3), the difference between stagnation and static pressures at the same location in the flow is 30 mm of mercury (density = 13600 kg m-3). Considering gravitational acceleration as 10 m s-2, the fluid speed (in m s-1) is ______________
    Correct answer is between '79,82'. Can you explain this answer?
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    In a steady and incompressible flow of a fluid (density = 1.25 kg m-3)...
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    In a steady and incompressible flow of a fluid (density = 1.25 kg m-3)...
    Given:
    - Density of fluid (ρ) = 1.25 kg/m³
    - Difference between stagnation and static pressures (ΔP) = 30 mmHg = 30 mm * 13.6 kg/m³ * 10 m/s² = 4080 kg/m²
    - Gravitational acceleration (g) = 10 m/s²

    To find:
    Fluid speed (V)

    Assumptions:
    - Steady flow
    - Incompressible flow

    Explanation:
    The difference between stagnation and static pressure at the same location in the flow is given by the Bernoulli's equation:

    ΔP = ρ * g * Δh + 0.5 * ρ * V²

    Where:
    - ΔP is the pressure difference
    - ρ is the density of the fluid
    - g is the gravitational acceleration
    - Δh is the difference in elevation (which is neglected in this case)
    - V is the fluid speed

    Solving the equation:
    We can rearrange the equation to solve for V:

    ΔP = 0.5 * ρ * V²

    V² = (2 * ΔP) / ρ

    V = sqrt((2 * ΔP) / ρ)

    Substituting the given values:

    V = sqrt((2 * 4080) / 1.25)
    = sqrt(6528)
    ≈ 80.79 m/s

    Conclusion:
    The fluid speed is approximately 80.79 m/s. Since the correct answer is between 79 and 82 m/s, the calculated value falls within this range.
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    In a steady and incompressible flow of a fluid (density = 1.25 kg m-3), the difference between stagnation and static pressures at the same location in the flow is 30 mm of mercury (density = 13600 kg m-3). Considering gravitational acceleration as 10 m s-2, the fluid speed (in m s-1) is ______________Correct answer is between '79,82'. Can you explain this answer?
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