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which calendar year will be same as the year 2008?
  • a)
    2018
  • b)
    2020
  • c)
    1980
  • d)
    1960
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
which calendar year will be same as the year 2008?a)2018b)2020c)1980d)...
For every 28 years, the calendars will same,
so the years 2008,2036 have the same calendar as 1980.
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Community Answer
which calendar year will be same as the year 2008?a)2018b)2020c)1980d)...
Explanation:
The Gregorian calendar repeats itself every 400 years, and the cycle of weekdays shifts by one day every 100 years. Therefore, to find out which year will be the same as the year 2008, we need to look for the year that is 28 years behind 2008 and belongs to the same cycle of weekdays.

- The year 2008 belongs to a cycle of weekdays that started in 1900.
- We can find the number of cycles of 100 years that have elapsed between 1900 and 2008 by dividing the difference by 100: (2008 - 1900) / 100 = 1.08.
- Since only whole cycles matter, we can ignore the decimal part and conclude that one cycle of 100 years has elapsed.
- Therefore, we need to subtract 100 years from 2008 to find a year that belongs to the same cycle of weekdays as 2008: 2008 - 100 = 1908.
- However, we are looking for a year that is 28 years behind 2008, so we need to add 28 years to 1908: 1908 + 28 = 1936.
- But 1936 is not a leap year (a year that has 366 days instead of 365), and 2008 is a leap year, so we need to add one more year to compensate: 1936 + 1 = 1937.
- Finally, we need to check if 1937 belongs to the same cycle of weekdays as 2008. To do this, we can divide 1937 by 4 (since there are 4 years in each cycle of leap years) and check the remainder: 1937 / 4 = 484 remainder 1.
- This means that 1937 is one year after the start of a cycle of weekdays that includes 2008. Therefore, we need to go back one more cycle of 100 years to find a year that belongs to the same cycle of weekdays as 2008: 1937 - 100 = 1837.
- But 1837 is too far back in time, so we need to go forward in time by another 80 years to find a year that is closer to 2008: 1837 + 80 = 1917.
- However, 1917 is not a leap year, so we need to add another year to compensate: 1917 + 1 = 1918.
- Finally, we need to check if 1918 belongs to the same cycle of weekdays as 2008. To do this, we can divide 1918 by 4 and check the remainder: 1918 / 4 = 479 remainder 2.
- This means that 1918 is two years after the start of a cycle of weekdays that includes 2008. Therefore, we need to go back two more cycles of 100 years to find a year that belongs to the same cycle of weekdays as 2008: 1918 - 200 = 1718.
- But 1718 is too far back in time, so we need to go forward in time by another 80 years to find a year that is closer to 2008: 1718 + 80 = 1798.
- However, 1798 is not a leap year, so we need to
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which calendar year will be same as the year 2008?a)2018b)2020c)1980d)1960Correct answer is option 'C'. Can you explain this answer?
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