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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
v(x) = βx-2n,
where β and n are constants and x is the position of the particle. The acceleration of the particle as a
function of x, is given by :
  • a)
    -2nβ2 e-4n + 1
  • b)
    -2nβ2 x-2n - 1
  • c)
    -2nβ2 x-4n - 1
  • d)
    -2nβ2 x-2n + 1
Correct answer is option 'C'. Can you explain this answer?
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A particle of unit mass undergoes one-dimensional motion such that its...
To continue the equation, we need the complete equation for the velocity, v(x). Without that information, we cannot provide a complete answer. Could you please provide the complete equation for v(x)?
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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according tov(x) = βx-2n,where β and n are constants and x is the position of the particle. The acceleration of the particle as afunction of x, is given by :a)-2nβ2 e-4n + 1b)-2nβ2x-2n -1c)-2nβ2 x-4n - 1d)-2nβ2x-2n +1Correct answer is option 'C'. Can you explain this answer?
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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according tov(x) = βx-2n,where β and n are constants and x is the position of the particle. The acceleration of the particle as afunction of x, is given by :a)-2nβ2 e-4n + 1b)-2nβ2x-2n -1c)-2nβ2 x-4n - 1d)-2nβ2x-2n +1Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle of unit mass undergoes one-dimensional motion such that its velocity varies according tov(x) = βx-2n,where β and n are constants and x is the position of the particle. The acceleration of the particle as afunction of x, is given by :a)-2nβ2 e-4n + 1b)-2nβ2x-2n -1c)-2nβ2 x-4n - 1d)-2nβ2x-2n +1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of unit mass undergoes one-dimensional motion such that its velocity varies according tov(x) = βx-2n,where β and n are constants and x is the position of the particle. The acceleration of the particle as afunction of x, is given by :a)-2nβ2 e-4n + 1b)-2nβ2x-2n -1c)-2nβ2 x-4n - 1d)-2nβ2x-2n +1Correct answer is option 'C'. Can you explain this answer?.
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