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A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is moving
Northwards with a speed of 10 km h-1. The time after which the distance between them becomes
shortest, is :
Northwards with a speed of 10 km h-1. The time after which the distance between them becomes
shortest, is :
- a)10√2h
- b)0 h
- c)5h
- d)5√2h
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 10...
It is clear from the diagram that the shortest distance between the ship A and B is PQ.
View all questions of this test
Most Upvoted Answer
A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 10...
The distance between the two ships can be calculated using the Pythagorean theorem.
Let's assume that the time after which the distance between them becomes shortest is t hours.
In t hours, ship A will have traveled a distance of 10t km towards the west.
In t hours, ship B will have traveled a distance of 10t km towards the north.
Using the Pythagorean theorem, the distance between the two ships after t hours can be calculated as:
distance = √((10t)^2 + 100^2)
To find the time after which the distance between them becomes shortest, we need to minimize the distance function.
Taking the derivative of the distance function with respect to t and setting it equal to zero will give us the time t at which the distance is minimized.
Let's differentiate the distance function:
d(distance)/dt = (1/2) * (10t)^(-1/2) * 2*10t + 0
Simplifying:
d(distance)/dt = 10
Setting this equal to zero and solving for t:
10 = 0
This equation has no solution, which means that the distance function does not have a minimum.
Therefore, the distance between the two ships will never become shortest.
So, there is no time after which the distance between them becomes shortest.
Let's assume that the time after which the distance between them becomes shortest is t hours.
In t hours, ship A will have traveled a distance of 10t km towards the west.
In t hours, ship B will have traveled a distance of 10t km towards the north.
Using the Pythagorean theorem, the distance between the two ships after t hours can be calculated as:
distance = √((10t)^2 + 100^2)
To find the time after which the distance between them becomes shortest, we need to minimize the distance function.
Taking the derivative of the distance function with respect to t and setting it equal to zero will give us the time t at which the distance is minimized.
Let's differentiate the distance function:
d(distance)/dt = (1/2) * (10t)^(-1/2) * 2*10t + 0
Simplifying:
d(distance)/dt = 10
Setting this equal to zero and solving for t:
10 = 0
This equation has no solution, which means that the distance function does not have a minimum.
Therefore, the distance between the two ships will never become shortest.
So, there is no time after which the distance between them becomes shortest.
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A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer?
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A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer?.
A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ship A is moving Westwards with a speed of 10 km h-1 and a ship B 100 km South of A, is movingNorthwards with a speed of 10 km h-1. The time after which the distance between them becomesshortest, is :a)10√2hb)0 hc)5hd)5√2hCorrect answer is option 'C'. Can you explain this answer?.
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