Solution:

Given, an unbiased coin is tossed 10 times.

Let's consider the first toss, there are two possible outcomes - Head or Tail. For the second toss, there are again two possible outcomes - Head or Tail. Similarly, for all the 10 tosses, there are two possible outcomes.

Therefore, the total number of possible outcomes = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 210

Now, we need to find the probability that all outcomes are the same.

Case 1: All outcomes are Heads

The probability of getting a Head in the first toss = 1/2
The probability of getting a Head in the second toss = 1/2
Similarly, for all 10 tosses, the probability of getting a Head = 1/2

Therefore, the probability of getting all Heads = (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) = 1/210

Case 2: All outcomes are Tails

The probability of getting a Tail in the first toss = 1/2
The probability of getting a Tail in the second toss = 1/2
Similarly, for all 10 tosses, the probability of getting a Tail = 1/2

Therefore, the probability of getting all Tails = (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) = 1/210

Hence, the total probability of getting all outcomes the same = probability of getting all Heads + probability of getting all Tails = 1/210 + 1/210 = 2/210

= 1/105

= 0.0095238

Therefore, the answer in scientific notation = 0.0095238 x 10^5

= 952.38 x 10^-2

= 9.5238 x 10^-1 x 10^-2

= 9.5238 x 10^-3

= 9,5238 in normal notation

Hence, the correct answer is between 191,199.