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The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formula α = a T, where a is a positive constant and T in ºC. If the length of the rod is l at temperature 0 ºC, then the temperature at which the length will be 2 l is:
  • a)
     
  • b)
  • c)
    1/α
  • d)
    2/α
Correct answer is option 'D'. Can you explain this answer?
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The co-efficient of thermal expansion of a rod is temperature dependen...

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The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formulaα = a T, where a is a positive constant and T in ºC. If the length of the rod is l at temperature 0 ºC, then the temperature at which the length will be 2 l is:a)b)c)1/αd)2/αCorrect answer is option 'D'. Can you explain this answer?
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The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formulaα = a T, where a is a positive constant and T in ºC. If the length of the rod is l at temperature 0 ºC, then the temperature at which the length will be 2 l is:a)b)c)1/αd)2/αCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formulaα = a T, where a is a positive constant and T in ºC. If the length of the rod is l at temperature 0 ºC, then the temperature at which the length will be 2 l is:a)b)c)1/αd)2/αCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formulaα = a T, where a is a positive constant and T in ºC. If the length of the rod is l at temperature 0 ºC, then the temperature at which the length will be 2 l is:a)b)c)1/αd)2/αCorrect answer is option 'D'. Can you explain this answer?.
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